Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 1)
1.
Determine the total discharge time for the capacitor in a clamper having C = 0.01 
F and R = 500 k
.
F and R = 500 k.Discussion:
21 comments Page 2 of 3.
Yogendra joshi said:
1 decade ago
Is R total circuit resistance ?
Ankita said:
1 decade ago
Exponential is a graph which vary in form of pow(e, t) this curve is drawn between frequency and time.
Hammad said:
1 decade ago
What is the meaning of exponential?
Arindam said:
1 decade ago
The Capacitor fully charge or discharge in 5 time constants.
So, 5*R*C= 25 ms.
So, 5*R*C= 25 ms.
Subhashis sharma said:
1 decade ago
What is the meaning of 98% in 5secs? how it can b derived?/.
Jumshed UET Lahore said:
1 decade ago
Actually capacitor discharges 98% in five time constant. You can verify using formula of capacitor discharge.
Vikram said:
1 decade ago
Time constant is the time required by Capacitor to get charge to or discharge to 63.2% of total voltage applied across it, so in one time constant it will be 0.63 of final value, in second it will be 0.63 of remaining aiming voltage. In this way capacitor will approximately take 5 time constants to get discharge.
Akila said:
1 decade ago
I want clear explanation why we said that 5 time constant.
Viswa said:
1 decade ago
Could any one explain How do we know capacitor charges and discharges in 5 time const ?
LOKESH said:
1 decade ago
Actually it takes infinite time since it is exponential process. But for practical purpose we take it as 5*time constant i.e, 5*RC
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