Electronic Devices - Diode Applications - Discussion
Discussion Forum : Diode Applications - General Questions (Q.No. 1)
1.
Determine the total discharge time for the capacitor in a clamper having C = 0.01 
F and R = 500 k
.
F and R = 500 k.Discussion:
21 comments Page 1 of 3.
Vijay Shinde said:
1 decade ago
The discharge voltage for the capacitor is given by:
VC (t) = Vo exp(-t/RC) for t > or = 0
Here, t exp(-t/RC)
t=1*RC 0.37
t=2*RC 0.14
t=3*RC 0.05
t=4*RC 0.02
t=5*RC 0.01
So that practically we say that after 5 time constant capacitor is fully charged/Discharged.
VC (t) = Vo exp(-t/RC) for t > or = 0
Here, t exp(-t/RC)
t=1*RC 0.37
t=2*RC 0.14
t=3*RC 0.05
t=4*RC 0.02
t=5*RC 0.01
So that practically we say that after 5 time constant capacitor is fully charged/Discharged.
Vikram said:
1 decade ago
Time constant is the time required by Capacitor to get charge to or discharge to 63.2% of total voltage applied across it, so in one time constant it will be 0.63 of final value, in second it will be 0.63 of remaining aiming voltage. In this way capacitor will approximately take 5 time constants to get discharge.
DINESH said:
1 decade ago
Actually there are two responses one is transient response and steady state response steady state response occurs after the output becomes constant so it is almost equal to transient response so the answer is 5*RC.
(1)
LOKESH said:
1 decade ago
Actually it takes infinite time since it is exponential process. But for practical purpose we take it as 5*time constant i.e, 5*RC
Jumshed UET Lahore said:
1 decade ago
Actually capacitor discharges 98% in five time constant. You can verify using formula of capacitor discharge.
Ankita said:
1 decade ago
Exponential is a graph which vary in form of pow(e, t) this curve is drawn between frequency and time.
Gangadhar reddy said:
1 decade ago
Yes, the answer is correct because we take 5 time constants in practical so the formula is 5*R*C.
(1)
Viswa said:
1 decade ago
Could any one explain How do we know capacitor charges and discharges in 5 time const ?
Arindam said:
1 decade ago
The Capacitor fully charge or discharge in 5 time constants.
So, 5*R*C= 25 ms.
So, 5*R*C= 25 ms.
Annanya said:
1 decade ago
How do we know capacitor charges and discharges in 5 time const ?
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