Electronic Devices - BJT Devices - Discussion
Discussion Forum : BJT Devices - General Questions (Q.No. 18)
18.
Calculate 
dc at VCE = 15 V and IB = 30 
A.
dc at VCE = 15 V and IB = 30 A. 
Discussion:
12 comments Page 1 of 2.
Isha said:
1 decade ago
explain how?
MANIKANDAN said:
1 decade ago
I want formula for this one.
Kaustav said:
1 decade ago
What is the formula behind it? how can we say 110 and not 116.
Deepthi said:
1 decade ago
We have to assume ic as 3.3 ma as v.ce and i(b) co insides at nearly 3.3
So beta=Ic/Ib= (3.3*10^-3)/(30*10^-6)=110
So beta=Ic/Ib= (3.3*10^-3)/(30*10^-6)=110
Venkatakrishna said:
1 decade ago
What is the difference between beta dc and beta ac?
Sunil said:
1 decade ago
According to me the answer should be 100 because B = Ic/Ib. And when you will put value in the formula will get answer.
(1)
Priya said:
1 decade ago
Firstly hfe is Bac suite of h-parameter and refers only to the CE configuration you can call it as AC current gain.
Bdc is a static (DC) parameter the DC current gain which gives rough idea of ac current gain, but is easier to measure. It is what indicated on simple transistor tester.
Bdc is a static (DC) parameter the DC current gain which gives rough idea of ac current gain, but is easier to measure. It is what indicated on simple transistor tester.
Nyce said:
1 decade ago
@Venkatakrishna.
Beta ac is change in Ic over change in Ib.
Beta ac is change in Ic over change in Ib.
Lucky said:
10 years ago
Beta ac = Delta (Ic)/Delta (Ib).
Beta dc = Ic/Ib.
Beta dc = Ic/Ib.
Prateek said:
9 years ago
But how? Please solve it.
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