Electronic Devices - BJT Devices - Discussion

Discussion Forum : BJT Devices - General Questions (Q.No. 18)
18.
Calculate dc at VCE = 15 V and IB = 30 A.

100
116
50
110
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
12 comments Page 1 of 2.

Ronald Ros said:   3 years ago
The concept of gain in AC is somewhat similar to the concept of DC. However, in AC, we use the gain as the change between two points. In this case, DC gain is more specific than AC.

Picking the near points in AC can be used as substitute for the Ic. In the example, 3 uA is for AC due to its nearest point in the trend.
(1)

Reico said:   7 years ago
B(dc) = IC/IB.
Given: IB = 30uA.
If you will see thoroughly the graph, there are small levels in horizontal lines. For example, in IC, it dropped in 3rd level(that is how I give term to it). so IC = 3.3mA.

B(dc) = 3.3mA / 30uA = 110.

Prateek said:   9 years ago
But how? Please solve it.

Lucky said:   10 years ago
Beta ac = Delta (Ic)/Delta (Ib).

Beta dc = Ic/Ib.

Nyce said:   1 decade ago
@Venkatakrishna.

Beta ac is change in Ic over change in Ib.

Priya said:   1 decade ago
Firstly hfe is Bac suite of h-parameter and refers only to the CE configuration you can call it as AC current gain.

Bdc is a static (DC) parameter the DC current gain which gives rough idea of ac current gain, but is easier to measure. It is what indicated on simple transistor tester.

Sunil said:   1 decade ago
According to me the answer should be 100 because B = Ic/Ib. And when you will put value in the formula will get answer.
(1)

Venkatakrishna said:   1 decade ago
What is the difference between beta dc and beta ac?

Deepthi said:   1 decade ago
We have to assume ic as 3.3 ma as v.ce and i(b) co insides at nearly 3.3

So beta=Ic/Ib= (3.3*10^-3)/(30*10^-6)=110

Kaustav said:   1 decade ago
What is the formula behind it? how can we say 110 and not 116.


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