Electronic Devices - BJT Devices - Discussion
Discussion Forum : BJT Devices - General Questions (Q.No. 18)
18.
Calculate 
dc at VCE = 15 V and IB = 30 
A.
dc at VCE = 15 V and IB = 30 A. 
Discussion:
12 comments Page 2 of 2.
Reico said:
7 years ago
B(dc) = IC/IB.
Given: IB = 30uA.
If you will see thoroughly the graph, there are small levels in horizontal lines. For example, in IC, it dropped in 3rd level(that is how I give term to it). so IC = 3.3mA.
B(dc) = 3.3mA / 30uA = 110.
Given: IB = 30uA.
If you will see thoroughly the graph, there are small levels in horizontal lines. For example, in IC, it dropped in 3rd level(that is how I give term to it). so IC = 3.3mA.
B(dc) = 3.3mA / 30uA = 110.
Ronald Ros said:
3 years ago
The concept of gain in AC is somewhat similar to the concept of DC. However, in AC, we use the gain as the change between two points. In this case, DC gain is more specific than AC.
Picking the near points in AC can be used as substitute for the Ic. In the example, 3 uA is for AC due to its nearest point in the trend.
Picking the near points in AC can be used as substitute for the Ic. In the example, 3 uA is for AC due to its nearest point in the trend.
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