Electrical Engineering - Voltage, Current and Resistance - Discussion

Discussion Forum : Voltage, Current and Resistance - General Questions (Q.No. 12)
12.
Eight-tenths coulomb passes a point in 4 s. The current in amperes is
1.6 A
16 A
2 A
0.2 A
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
42 comments Page 4 of 5.

Suresh said:   8 years ago
Thank you @Prashant.

Yevuna Frederick said:   8 years ago
You are right @Prashant.

Saroj said:   8 years ago
q =it.
=> i = q/t.
q = 8/10 = 0.8, t=4.
i = 0.8/4 = 0.2.A.

JAKAPURE ABHISHEK said:   8 years ago
Q=8/10=0.8,
T= 4.

We know,
I= charge/time,
I= 0.8/4,
I=0.2amp.

And is option D.
(7)

Sachin nityanand nikose said:   8 years ago
I = q/t.
I = 8/10/4,
I = 8/10*4,
I = 8/40,
I = 0.2Amp.
(11)

Mohd imran said:   7 years ago
I have a doubt. How come 8/10?

Why not 8*10?

Please give the answer.
(1)

Girija said:   7 years ago
Well said @Prashant.
(2)

Mazharul islam said:   5 years ago
0.8/4=0.2.
(4)

Omendra said:   5 years ago
Q=it Q= 8c or 10c t= 4 sec.
i=10/4=2.5A
i=8/4=2A.

2.5A is not given in the option, so the answer Will be 2A.
(7)

Anwar said:   2 years ago
Here the mention time (4s) only
But why you guys take
Q=8/10?
Is there any farmula? Please explain me.
(2)


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