Electrical Engineering - Voltage, Current and Resistance - Discussion
Discussion Forum : Voltage, Current and Resistance - General Questions (Q.No. 12)
12.
Eight-tenths coulomb passes a point in 4 s. The current in amperes is
Discussion:
42 comments Page 5 of 5.
ANUPU PENCHALAIAH said:
2 years ago
First, we need to observe the question very carefully they mentioned that Eight-tenths (8/10).
So, I = Q/t.
= 8/10*4.
= 2/10.
= 0.2.
i=0.2 amperes.
So, I = Q/t.
= 8/10*4.
= 2/10.
= 0.2.
i=0.2 amperes.
(8)
Manas sethi said:
12 months ago
To find the current in amperes, we can use the formula:
Current (I) = Charge (Q)/Time (t).
Given:
Charge (Q) = 8/10 Coulomb = 0.8 Coulomb,
Time (t) = 4 seconds.
Plugging in the values, we get:
I = Q/t.
= 0.8 C/4 s,
= 0.2 A.
So, the current is 0.2 amperes.
Current (I) = Charge (Q)/Time (t).
Given:
Charge (Q) = 8/10 Coulomb = 0.8 Coulomb,
Time (t) = 4 seconds.
Plugging in the values, we get:
I = Q/t.
= 0.8 C/4 s,
= 0.2 A.
So, the current is 0.2 amperes.
(8)
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