Electrical Engineering - Voltage, Current and Resistance - Discussion
Discussion Forum : Voltage, Current and Resistance - General Questions (Q.No. 12)
12.
Eight-tenths coulomb passes a point in 4 s. The current in amperes is
Discussion:
42 comments Page 1 of 5.
Sujush said:
1 decade ago
Try this i=di/dt.
Prashant said:
1 decade ago
Q = 8/10 given;
t = 4 s
Now current i = Q / t
i = (8/10)/4
i = 2/10;
i = 0.2 A
t = 4 s
Now current i = Q / t
i = (8/10)/4
i = 2/10;
i = 0.2 A
(1)
Santhu said:
1 decade ago
Yes prashanth is correct.
Hussain said:
1 decade ago
Prashanth is correct
Dhanaji Wakade said:
1 decade ago
Yes Q= i*t also remeber Q=C*V
Arshiya naaz said:
1 decade ago
Yes rashant is correct.
Santosh kumar pattayat said:
1 decade ago
Yes prasanta you are write.
Keerthi said:
1 decade ago
@Prashanth is correct.
Ankit said:
1 decade ago
Prashanth is correct
Surajit said:
1 decade ago
Q = 8/10
t = 4 s
Now current i = Q / t that means current=charge/time
i = (8/10)/4
i = 2/10;
i = 0.2 A
t = 4 s
Now current i = Q / t that means current=charge/time
i = (8/10)/4
i = 2/10;
i = 0.2 A
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