Electrical Engineering - Voltage, Current and Resistance - Discussion
Discussion Forum : Voltage, Current and Resistance - General Questions (Q.No. 12)
12.
Eight-tenths coulomb passes a point in 4 s. The current in amperes is
Discussion:
42 comments Page 2 of 5.
Ashutosh said:
1 decade ago
Q = 8/10 = 0.8.
t = 4s.
I = Q/t.
= 0.8/4
= 0.2A.
t = 4s.
I = Q/t.
= 0.8/4
= 0.2A.
AVADHESH KUMAR said:
1 decade ago
Yes q=i*t means charge=current*time.
So q=8/10 &t=4s.
So i=q/t=8/10/4=0.2 A.
So q=8/10 &t=4s.
So i=q/t=8/10/4=0.2 A.
Veeru said:
1 decade ago
Total charge Q = I*T.
Thereforre I=Q/T.
I=(8/10)/4
=(8/10)*(1/4)
=2/10
I=0.2A.
Thereforre I=Q/T.
I=(8/10)/4
=(8/10)*(1/4)
=2/10
I=0.2A.
ZUBAIR AHAMED said:
1 decade ago
Charge/coulombs Q = I*T.
So I = Q/T.
I = 8/(10*4).
I = 0.2A.
So I = Q/T.
I = 8/(10*4).
I = 0.2A.
ABDUL AZIZ(gcettb 2nd yr ,EE ) said:
1 decade ago
Q=8/10 c,
t=4 sec,
we know that,
I = Q/t(current = charge/time).
So I = (8/10)/4.
= 0.2A.
t=4 sec,
we know that,
I = Q/t(current = charge/time).
So I = (8/10)/4.
= 0.2A.
P.VEERAMANI said:
1 decade ago
Here, Q = i*t.
Then 8/10 = i*4s.
Hence i = 0.2A.
Then 8/10 = i*4s.
Hence i = 0.2A.
Praveen Raj said:
1 decade ago
Q = 8/10 = 0.8.
T = 4.
I = Q/T.
I = 0.8/4.
I = 0.2.
T = 4.
I = Q/T.
I = 0.8/4.
I = 0.2.
HARILAL said:
1 decade ago
Q = 8/10 = 0.8.
T = 4.
I = Q/T.
I = 0.8/4.
I = 0.2.
T = 4.
I = Q/T.
I = 0.8/4.
I = 0.2.
Brahma krishna said:
1 decade ago
i = q\t.
q = 8/10 = 0.8.
i = 0.8/4 = 0.2.
q = 8/10 = 0.8.
i = 0.8/4 = 0.2.
Himanshu Arya said:
1 decade ago
Given, t = 4 sec, Q = 8/10 C.
We know that charge is directly proportional to current and time i.e. Q = it.
i = Q/t.
i = (8/10)/4.
i = 0.8/4.
i = 0.2 amp.
We know that charge is directly proportional to current and time i.e. Q = it.
i = Q/t.
i = (8/10)/4.
i = 0.8/4.
i = 0.2 amp.
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