Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 1)
1.
What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?
Discussion:
121 comments Page 9 of 13.
K.vijay anand said:
1 decade ago
KVA = ( VOLTS * AMP )/1000 = ( 2000 * 8 ) /1000 = 16
Venkatesh said:
1 decade ago
Suppose 2kv is given as 2v then what is the answer.
Garima said:
10 years ago
In short circuit test iron loss is negligible why?
Sree said:
9 years ago
kva rating = v × i = 2000 × 8 = 16000.
Abhishek said:
8 years ago
Why transformer's rating is in Kva and not in Kw?
(4)
Gyanprakash said:
9 years ago
Thank you for all the solution and explanation.
Lingam Nayak said:
1 decade ago
It's simple v2*i2=2kv*8
=16kv
=16kv
Raghaba Pradhan said:
1 decade ago
Put the formula and get the answer KVA = VI.
Praveen j said:
8 years ago
V2*i2 = kVa.
So,
2* 8= 16 kVa.
Ans:- 16 kVa.
So,
2* 8= 16 kVa.
Ans:- 16 kVa.
(1)
Siri said:
1 decade ago
Here how we can assume power-factor values?
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