Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 1)

Transformers

What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?

4 kVA

0.25 kVA

16 kVA

8 kVA

Answer: Option

Explanation:

No answer description is available. Let's discuss.

Discussion:

121 comments Page 8 of 13.

Akshay said: 1 decade ago

Can we change the rating of transformer by using some method?

P.H.Hussain said: 1 decade ago

We know that,
Power P=voltage*current
P=2*8=16kw (or) 16kVA.

Ranjith kumar said: 1 decade ago

By using parallel operation load share equally in every T/R.

Azhagu said: 1 decade ago

Output = Max I x Secondary voltage

= 8A *2000 V

= 16 KVA.

Vishwanath said: 1 decade ago

Sudhandiran K said really well nice explaination........

Narendra said: 1 decade ago

p=vi
p=kva
v=2kv=2*1000v
i=8a
p=8*2*1000=16000va
p=16kva

SAKTHIMADHAN said: 10 years ago

V*A = VA.
2000*8 = 1600 VA.

KVA = 1600/1000.
KVA = 16.

Arvind chaudhari said: 1 decade ago

KVA = (V*A)/1000 => (16000/8) => 16.

KVA = 16.

Akash said: 1 decade ago

KVA = Kilovolt * Ampere.
KVA = 2KV * 8A.
KVA = 16KVA.

Jitendra Patel said: 1 decade ago

KVA = ( VOLTS * AMP )/1000 = ( 2000 * 8 ) /1000 = 16

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