Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 1)
1.
What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?
Discussion:
121 comments Page 10 of 13.
Nisha Thakur said:
2 years ago
KW = KVA,
P= VI.
KVA rating = 2*8 = 16 KVA.
P= VI.
KVA rating = 2*8 = 16 KVA.
(3)
Gautam said:
1 decade ago
KVA=(V*A)/1000=>(16000/8)=>16
KVA=16
KVA=16
Raihan said:
1 decade ago
The 3rd winding of a transformer called ?
Navneet kumar said:
1 decade ago
kva
=volt*ampere/1000
=2000*8/1000
=16
=volt*ampere/1000
=2000*8/1000
=16
ROOPESH said:
7 years ago
Have any formula for change to kW to ka?
(5)
SOULMAKER said:
2 years ago
KVA = A * KV.
= 8 * 2.
KVA = 16.
= 8 * 2.
KVA = 16.
(3)
Sankar said:
1 decade ago
kva=V*I
kva=2000*8
=16000
=16kva
kva=2000*8
=16000
=16kva
Vinoth said:
1 decade ago
What is mean of isolation transformer?
Vishal said:
1 decade ago
What is mean of isolation transformer?
Madhav said:
1 decade ago
It is simple.
p = v*i.
= 8*2.
= 16.
p = v*i.
= 8*2.
= 16.
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