Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 1)
1.
What kVA rating is required for a transformer that must handle a maximum load current of 8 A with a secondary voltage of 2 kV?
Discussion:
121 comments Page 11 of 13.
MOHAMED MANSOOR said:
1 decade ago
V2*I2=2*8=16.
Here load current=I2=8A
Here load current=I2=8A
Priya said:
1 decade ago
Q=v*i*10^-3
Q=20000*8*10^-3
Q=16kva
Q=20000*8*10^-3
Q=16kva
Sachin said:
9 years ago
@All.
Thanks for the explanation.
Thanks for the explanation.
Akshay said:
1 decade ago
What is more loss in transformer?
Manukumari.m said:
1 decade ago
KVA/KV = I.
KVA/2 = 8.
KVA = 16.
KVA/2 = 8.
KVA = 16.
Ramniwas said:
8 years ago
Thanks to all your explanation.
(1)
SUMIT said:
1 decade ago
Kva = V *I = 2KV* 8A = 16 KVA.
UJJAWAL PATLE said:
9 years ago
v * A = 2000 * 8\1000 = 16kva.
Rohit said:
1 decade ago
kva=v1/v2=i2/i1
is this right
is this right
RANJIT RAI said:
8 years ago
Thanks all for explaining it.
(1)
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