Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 6)
6.
The primary winding of a transformer has 110 V ac across it. What is the secondary voltage if the turns ratio is 8?
Answer: Option
Explanation:
V2/V1 = N2/N1
Turns ratio = N2/N1 = 8.
V2/110 = 8
V2 = 8 x 110
V2 = 880v.
Discussion:
24 comments Page 3 of 3.
Dhanasekar said:
1 decade ago
Turns ratio=N2/N1
I1/I2=N2/N1=E2/E1
so,E2/E1=8:
E1=110
sub the E1 value
E2=8*110=880V
I1/I2=N2/N1=E2/E1
so,E2/E1=8:
E1=110
sub the E1 value
E2=8*110=880V
Prasanna said:
1 decade ago
Ns=8
Np=1 Ns/Np=Vs/Vp
Vp=110v 8/1 =Vs/110(by cross mult)
Vs=? Vs=8*110
= 880v
Np=1 Ns/Np=Vs/Vp
Vp=110v 8/1 =Vs/110(by cross mult)
Vs=? Vs=8*110
= 880v
K.Ashok kumar said:
1 decade ago
n2/n1=v2/v1.
so given that
n2/n1=8 & v1=110
there for v2=(n2/n1)*v1
so v2=880
so given that
n2/n1=8 & v1=110
there for v2=(n2/n1)*v1
so v2=880
KUNAL said:
1 decade ago
Turns Ratio = 8, V1=110
V2 = 8*110 = 880.
V2 = 8*110 = 880.
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