Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 6)
6.
The primary winding of a transformer has 110 V ac across it. What is the secondary voltage if the turns ratio is 8?
8.8 V
88 V
880 V
8,800 V
Answer: Option
Explanation:

V2/V1 = N2/N1

Turns ratio = N2/N1 = 8.

V2/110 = 8

V2 = 8 x 110

V2 = 880v.

Discussion:
24 comments Page 1 of 3.

Loganathan said:   1 decade ago
N1/N2=V1/V2
1/8=110/V2
V2=110*8/1
V2=880V

KUNAL said:   1 decade ago
Turns Ratio = 8, V1=110

V2 = 8*110 = 880.

K.Ashok kumar said:   1 decade ago
n2/n1=v2/v1.
so given that
n2/n1=8 & v1=110
there for v2=(n2/n1)*v1
so v2=880

Prasanna said:   1 decade ago
Ns=8
Np=1 Ns/Np=Vs/Vp
Vp=110v 8/1 =Vs/110(by cross mult)
Vs=? Vs=8*110
= 880v

Dhanasekar said:   1 decade ago
Turns ratio=N2/N1
I1/I2=N2/N1=E2/E1
so,E2/E1=8:
E1=110
sub the E1 value
E2=8*110=880V

Sumit M.kalamkar said:   1 decade ago
N2/N1 =V1/v2
N2/110 =8
N2 =8*110
N2 =880v

Anuraj yadav said:   1 decade ago
v2 = turn ratio/v1
v2 = 110*8
v2 = 880 ans

Alakhya said:   1 decade ago
Turns ratio is inverse of transformation ratio transformation ratio is N2/N1 this answer is wrong.

Yogendra said:   1 decade ago
V2/V1 = N2/N1.

V2/110 = 8.

V2 = 880V.

Amit said:   1 decade ago
V2/V1 = N2/N1.

Given Turns ratio = N2/N1 = 8.

V2/110 = 8.

V2 = 8 x 110.

V2 = 880V. Answer C.


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