Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 6)
6.
The primary winding of a transformer has 110 V ac across it. What is the secondary voltage if the turns ratio is 8?
8.8 V
88 V
880 V
8,800 V
Answer: Option
Explanation:

V2/V1 = N2/N1

Turns ratio = N2/N1 = 8.

V2/110 = 8

V2 = 8 x 110

V2 = 880v.

Discussion:
24 comments Page 2 of 3.

Umesh said:   10 years ago
Wrong answer are there. First need to clear what is turns ratios?

It N1/ N2. Then answer comes 13.75 v.

Sainath goud said:   1 decade ago
N1/N2 = V2/V1.

Given that N1/N2 = 8.

8*110 = 880 = V2.

So answer is "C".

Loganathan said:   1 decade ago
N1/N2=V1/V2
1/8=110/V2
V2=110*8/1
V2=880V

Mounesh said:   1 decade ago
V1 = 110V.
N1 = 8.
V2 = ?

K = 1/N1.
K = 1/8.
K = 0.125.

V2 = V1/K.
V2 = 110/8.
V2 = 880V.

Hariharan said:   1 decade ago
880v is answer.

V2 = ( (N2/N1) *V1).

So V2 = 8*110.

V2 = 880.

Amit said:   1 decade ago
V2/V1 = N2/N1.

Given Turns ratio = N2/N1 = 8.

V2/110 = 8.

V2 = 8 x 110.

V2 = 880V. Answer C.

Yogendra said:   1 decade ago
V2/V1 = N2/N1.

V2/110 = 8.

V2 = 880V.

Alakhya said:   1 decade ago
Turns ratio is inverse of transformation ratio transformation ratio is N2/N1 this answer is wrong.

Anuraj yadav said:   1 decade ago
v2 = turn ratio/v1
v2 = 110*8
v2 = 880 ans

Sumit M.kalamkar said:   1 decade ago
N2/N1 =V1/v2
N2/110 =8
N2 =8*110
N2 =880v


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