Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 6)
6.
The primary winding of a transformer has 110 V ac across it. What is the secondary voltage if the turns ratio is 8?
Answer: Option
Explanation:
V2/V1 = N2/N1
Turns ratio = N2/N1 = 8.
V2/110 = 8
V2 = 8 x 110
V2 = 880v.
Discussion:
24 comments Page 2 of 3.
Sainath goud said:
1 decade ago
N1/N2 = V2/V1.
Given that N1/N2 = 8.
8*110 = 880 = V2.
So answer is "C".
Given that N1/N2 = 8.
8*110 = 880 = V2.
So answer is "C".
Akash.bhure said:
1 decade ago
Solution:
Turns ratio (K) = 8.
Primary voltage = 110v.
N2/N1 = V2/V1.
V2 = N2/N1*V1.
V2 = 8*110 = 880V.
Turns ratio (K) = 8.
Primary voltage = 110v.
N2/N1 = V2/V1.
V2 = N2/N1*V1.
V2 = 8*110 = 880V.
Mounesh said:
1 decade ago
V1 = 110V.
N1 = 8.
V2 = ?
K = 1/N1.
K = 1/8.
K = 0.125.
V2 = V1/K.
V2 = 110/8.
V2 = 880V.
N1 = 8.
V2 = ?
K = 1/N1.
K = 1/8.
K = 0.125.
V2 = V1/K.
V2 = 110/8.
V2 = 880V.
Hariharan said:
1 decade ago
880v is answer.
V2 = ( (N2/N1) *V1).
So V2 = 8*110.
V2 = 880.
V2 = ( (N2/N1) *V1).
So V2 = 8*110.
V2 = 880.
Amit said:
1 decade ago
V2/V1 = N2/N1.
Given Turns ratio = N2/N1 = 8.
V2/110 = 8.
V2 = 8 x 110.
V2 = 880V. Answer C.
Given Turns ratio = N2/N1 = 8.
V2/110 = 8.
V2 = 8 x 110.
V2 = 880V. Answer C.
Yogendra said:
1 decade ago
V2/V1 = N2/N1.
V2/110 = 8.
V2 = 880V.
V2/110 = 8.
V2 = 880V.
Alakhya said:
1 decade ago
Turns ratio is inverse of transformation ratio transformation ratio is N2/N1 this answer is wrong.
Anuraj yadav said:
1 decade ago
v2 = turn ratio/v1
v2 = 110*8
v2 = 880 ans
v2 = 110*8
v2 = 880 ans
Sumit M.kalamkar said:
1 decade ago
N2/N1 =V1/v2
N2/110 =8
N2 =8*110
N2 =880v
N2/110 =8
N2 =8*110
N2 =880v
Dhanasekar said:
1 decade ago
Turns ratio=N2/N1
I1/I2=N2/N1=E2/E1
so,E2/E1=8:
E1=110
sub the E1 value
E2=8*110=880V
I1/I2=N2/N1=E2/E1
so,E2/E1=8:
E1=110
sub the E1 value
E2=8*110=880V
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