Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 
?
?250
25
6,250
62,500
Discussion:
46 comments Page 4 of 5.
Santosh murkut said:
9 years ago
The transformation ratio is said that N2/N1 = V2/V1 = I1/I2 = K.
Hence,
1) A resistance R1 in primary become K^2 * R1 when transferred to the secondary.
2) A resistance R2 in secondary become R2 / K^2 when transferred to the primary.
Therefore,
R1 = 250 / (10/50)^2 = 6250 ohm.
Hence,
1) A resistance R1 in primary become K^2 * R1 when transferred to the secondary.
2) A resistance R2 in secondary become R2 / K^2 when transferred to the primary.
Therefore,
R1 = 250 / (10/50)^2 = 6250 ohm.
Vyankatesh badgujar said:
9 years ago
N1= 50 , N2 = 10.
Turn ratio K = N2/N1 = 10/50,
K = 1/5 = 0.2,
Now, R2/R1 = K^2.
R1 = R2/K^2,
= 250/0.2^2,
R1 = 6250 ohms.
Turn ratio K = N2/N1 = 10/50,
K = 1/5 = 0.2,
Now, R2/R1 = K^2.
R1 = R2/K^2,
= 250/0.2^2,
R1 = 6250 ohms.
(1)
Sandeep Kumar said:
9 years ago
N2/N1= Sq.rt(R2/R1)
10/50 = Sq.Rt(250/R1)
(1/5)^2 = 250/R1.
R1=250*25 = 6250.
10/50 = Sq.Rt(250/R1)
(1/5)^2 = 250/R1.
R1=250*25 = 6250.
(1)
Arjun said:
9 years ago
Reflective resistance = {(1/k^2)*Rload}.
ROCKY said:
9 years ago
Transformation ratio is N2/N1. Am I right?
(1)
Faisal said:
8 years ago
The Formula is this, R1=(N1/N2)^2 RL.
and R1 is given, N1 is given, N2 is given,
So, 250=(50/10)^2 RL.
250 = 25 RL.
Therefore, RL = 250 * 25 = 6250.
and R1 is given, N1 is given, N2 is given,
So, 250=(50/10)^2 RL.
250 = 25 RL.
Therefore, RL = 250 * 25 = 6250.
(2)
Tom said:
8 years ago
Here, n2/n1=r1/r2.
Paul said:
8 years ago
Ododo is the only one making sense here.
k = turns ratio = N2/N1 (This is most often the conclusion based on the 20mins I've spent on the web researching this).
k = turns ratio = N2/N1 (This is most often the conclusion based on the 20mins I've spent on the web researching this).
(2)
Sumit said:
8 years ago
If primary side 1000 turn and 1000 watt on primary side find out secondary side pawer in watt if seconady turn 100.
(1)
TUTUN MONDAL said:
8 years ago
K=N2/N1=1/5.
SECONDARY TO PRIMARY R1=R2/K^2 =250/(1/5)^2=250*25=6250OHMS.
SECONDARY TO PRIMARY R1=R2/K^2 =250/(1/5)^2=250*25=6250OHMS.
(5)
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