Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 ?
250
25
6,250
62,500
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
46 comments Page 1 of 5.

Mahendra chauhan said:   1 decade ago
# given data primary coil turns=50,secondary coil turns=10 & secondary load 250 ohm.

#equation N=secondary coil turns/primary coil turns
(Rpri=reflected in to primary)
Rpri=(1/n)^2*RL
so N =10/50
=0.2
Rpri =(1/0.2)^2*250

=(5)^2*250
=25*250
=6250.

Abhishek mohapatra said:   8 years ago
From the basics:

You have to find what resistance on primary will have similar effect as 250 on secondary.
in ideal transformer power associated with primary equals secondary hence V2^2/250 = v1^2/Rreq. similarly V2*I2 =V1*I1. if you know what voltages are related in the same way as a number of turns i.e V2/V1 = N2/N1 then you can easily relate all currents and impedances.

Eshan Mishra said:   1 decade ago
There is difference b/w the terms if simply turn ratio, voltage ratio is mention and transformation ratio is mention in the question.

Eg:- transformation ratio is k, k=[V2/V1=N2/N1=I1/I2].

Simple turn ratio, voltage ratio is equal to 1/k
N1/N2, V1/V2.

And there is one more important relation,
(V2/V1)=Square root(R2/R1).

Akash.bhure said:   1 decade ago
Solution:

No.of turns in the primary(N1) = 50.

No.of turns in the secondary(N2) = 10.

Turns ratio(K) = N2/N1 = 10/50 = 0.2.

Secondary load resistance(R2) = 250 Ohm.

Reflective resistance(R1) = R2/K^2.

(R1) = 250/(0.2)^2.
(R1) = 250/0.04 = 6250 ohm's.

Virendra ranpise said:   1 decade ago
Resistance ratio=R2/R1
Xmer ratio(K)=N2/N1
Where,
R1=Primary winding resistance
R2=secondary winding resistance
N1=Primari winding turns
N2=secondary winding turns
FORMULA FOR CALCULATING R1
R2/R1 = K square
i.e. R2/R1 = (N2/N1)square

250/R1 = (10/50) square
So
R1 = (250) / ((10/50) square)
R2=6250 ohm

Santosh murkut said:   9 years ago
The transformation ratio is said that N2/N1 = V2/V1 = I1/I2 = K.

Hence,

1) A resistance R1 in primary become K^2 * R1 when transferred to the secondary.

2) A resistance R2 in secondary become R2 / K^2 when transferred to the primary.

Therefore,

R1 = 250 / (10/50)^2 = 6250 ohm.

Sanjeev Kr. Rajoria said:   1 decade ago
Transformation ratio a = N1/N2
so
a=50/10=5
now
load resistance referred to primary= (a^2)*(load resistance)
so
the reflected load = 5^2*250
= 25*250
= 6250 ohm
So the correct ans is (c)= 6250 ohm

S.ANJINEYULU NAIK said:   1 decade ago
Turn ratio, k=N2/N1.

=10/50.

=1/5=0.2.

Actual resistance in secondary circuit is R2=250 ohm's.

Reflective resistance means, the secondary resistance referred to primary winding is,

R2'=R2/k^2.

=250/ (0.2) ^2.

=250/0.04.

=6250 ohm's.

Suresh said:   4 years ago
Voltage of secondary 200v, transformer ration N1:N2= 200:100, X=12 Ohms and Rl = 4 Ohms.
Estimate the RMS value of the primary current I1 and Secondary Current I2 and Estimate the power in watts.

Ododo said:   1 decade ago
Please am confused, turns ratio is it the same as transformer ratio?

I saw that turns ratio = N2/N1, and I still saw that turns ratio = N1/N2, which one is correct with proofs please.


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