Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 
?
?250
25
6,250
62,500
Discussion:
46 comments Page 2 of 5.
Majid Mahmood said:
6 years ago
According to my calaculation:
v1i1 = v2i2
v1*v1/r1 = v2*v2/r2
(v1/v2)^2 = r1/r2.
We know n1/n2 = v1/v2
so (50/10)^2 = r1/250 => 25 = r1/250,
r1 = 250 * 25 = 6250.
v1i1 = v2i2
v1*v1/r1 = v2*v2/r2
(v1/v2)^2 = r1/r2.
We know n1/n2 = v1/v2
so (50/10)^2 = r1/250 => 25 = r1/250,
r1 = 250 * 25 = 6250.
(12)
Paul said:
8 years ago
Ododo is the only one making sense here.
k = turns ratio = N2/N1 (This is most often the conclusion based on the 20mins I've spent on the web researching this).
k = turns ratio = N2/N1 (This is most often the conclusion based on the 20mins I've spent on the web researching this).
(2)
Faisal said:
8 years ago
The Formula is this, R1=(N1/N2)^2 RL.
and R1 is given, N1 is given, N2 is given,
So, 250=(50/10)^2 RL.
250 = 25 RL.
Therefore, RL = 250 * 25 = 6250.
and R1 is given, N1 is given, N2 is given,
So, 250=(50/10)^2 RL.
250 = 25 RL.
Therefore, RL = 250 * 25 = 6250.
(2)
Nidhi M J said:
1 decade ago
Copper losses produced by r2 in primary side must be same as that in secondary side.
I1^2*r2'=I2^2*r2
R2'= (I2/I1) ^2*r2
Where I2/I1=N1/N2.
I1^2*r2'=I2^2*r2
R2'= (I2/I1) ^2*r2
Where I2/I1=N1/N2.
Vyankatesh badgujar said:
9 years ago
N1= 50 , N2 = 10.
Turn ratio K = N2/N1 = 10/50,
K = 1/5 = 0.2,
Now, R2/R1 = K^2.
R1 = R2/K^2,
= 250/0.2^2,
R1 = 6250 ohms.
Turn ratio K = N2/N1 = 10/50,
K = 1/5 = 0.2,
Now, R2/R1 = K^2.
R1 = R2/K^2,
= 250/0.2^2,
R1 = 6250 ohms.
(1)
Amit Ranjan said:
1 decade ago
Eqv.resistance referred to primary=r1+r2/(k*k)
Here r1 is not given
k=10/50=1/5
Hence ans = 250/(1/25) = 6250 ohm.
Here r1 is not given
k=10/50=1/5
Hence ans = 250/(1/25) = 6250 ohm.
Sumit said:
8 years ago
If primary side 1000 turn and 1000 watt on primary side find out secondary side pawer in watt if seconady turn 100.
(1)
Engr. Mamoona Akbar said:
1 decade ago
t2/t1 = sqrt (load impedance/source impedance).
10/50 = sqrt (250/x).
0.2*0.2 = 250/x.
x = 250/0.04.
x = 6250.
10/50 = sqrt (250/x).
0.2*0.2 = 250/x.
x = 250/0.04.
x = 6250.
Kalyan said:
1 decade ago
Rs=250
I1^2Rs=I2^2Rf
(I1/I2)^2*Rs=Rf
From Transformation ratio N2/N1=I1/I2=K
(50/10)^2*250=Rf
25*250=Rf
Rf=6250ohm
I1^2Rs=I2^2Rf
(I1/I2)^2*Rs=Rf
From Transformation ratio N2/N1=I1/I2=K
(50/10)^2*250=Rf
25*250=Rf
Rf=6250ohm
Akshat gupta said:
1 decade ago
Where
n1=50
n2=10
r2=250ohm
so
resistance matching r1= (n1/n2)^*rl
hence,
r1=(50/10)^2*250
=25*250
=6250 ohm
n1=50
n2=10
r2=250ohm
so
resistance matching r1= (n1/n2)^*rl
hence,
r1=(50/10)^2*250
=25*250
=6250 ohm
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