Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 ?
250
25
6,250
62,500
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
46 comments Page 1 of 5.

Majid Mahmood said:   6 years ago
According to my calaculation:

v1i1 = v2i2
v1*v1/r1 = v2*v2/r2
(v1/v2)^2 = r1/r2.

We know n1/n2 = v1/v2
so (50/10)^2 = r1/250 => 25 = r1/250,
r1 = 250 * 25 = 6250.
(12)

HRD said:   2 years ago
R1 = (N1/N2)^2 * RL,
R1 = (50/10)^2 * 250,
R1 = 6250.
(6)

TUTUN MONDAL said:   8 years ago
K=N2/N1=1/5.

SECONDARY TO PRIMARY R1=R2/K^2 =250/(1/5)^2=250*25=6250OHMS.
(5)

Faisal said:   8 years ago
The Formula is this, R1=(N1/N2)^2 RL.
and R1 is given, N1 is given, N2 is given,
So, 250=(50/10)^2 RL.
250 = 25 RL.
Therefore, RL = 250 * 25 = 6250.
(2)

Paul said:   8 years ago
Ododo is the only one making sense here.
k = turns ratio = N2/N1 (This is most often the conclusion based on the 20mins I've spent on the web researching this).
(2)

Vaibhav said:   7 years ago
Can I find reflected impedance or turns ratio if the only efficiency of the transformer is provided?
(1)

Sumit said:   8 years ago
If primary side 1000 turn and 1000 watt on primary side find out secondary side pawer in watt if seconady turn 100.
(1)

ROCKY said:   8 years ago
Transformation ratio is N2/N1. Am I right?
(1)

Sandeep Kumar said:   9 years ago
N2/N1= Sq.rt(R2/R1)
10/50 = Sq.Rt(250/R1)
(1/5)^2 = 250/R1.
R1=250*25 = 6250.
(1)

Vyankatesh badgujar said:   9 years ago
N1= 50 , N2 = 10.

Turn ratio K = N2/N1 = 10/50,
K = 1/5 = 0.2,
Now, R2/R1 = K^2.

R1 = R2/K^2,
= 250/0.2^2,
R1 = 6250 ohms.
(1)


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