Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 
?
?250
25
6,250
62,500
Discussion:
46 comments Page 2 of 5.
Eshan Mishra said:
1 decade ago
There is difference b/w the terms if simply turn ratio, voltage ratio is mention and transformation ratio is mention in the question.
Eg:- transformation ratio is k, k=[V2/V1=N2/N1=I1/I2].
Simple turn ratio, voltage ratio is equal to 1/k
N1/N2, V1/V2.
And there is one more important relation,
(V2/V1)=Square root(R2/R1).
Eg:- transformation ratio is k, k=[V2/V1=N2/N1=I1/I2].
Simple turn ratio, voltage ratio is equal to 1/k
N1/N2, V1/V2.
And there is one more important relation,
(V2/V1)=Square root(R2/R1).
Arun Kumar Raju C said:
1 decade ago
Ns/Np = sqrt(load resistance/source resistance).
Akash.bhure said:
1 decade ago
Solution:
No.of turns in the primary(N1) = 50.
No.of turns in the secondary(N2) = 10.
Turns ratio(K) = N2/N1 = 10/50 = 0.2.
Secondary load resistance(R2) = 250 Ohm.
Reflective resistance(R1) = R2/K^2.
(R1) = 250/(0.2)^2.
(R1) = 250/0.04 = 6250 ohm's.
No.of turns in the primary(N1) = 50.
No.of turns in the secondary(N2) = 10.
Turns ratio(K) = N2/N1 = 10/50 = 0.2.
Secondary load resistance(R2) = 250 Ohm.
Reflective resistance(R1) = R2/K^2.
(R1) = 250/(0.2)^2.
(R1) = 250/0.04 = 6250 ohm's.
Sandip chhatrola said:
1 decade ago
K^2 = R2/R1.
1/25 = 250/R1.
R1 = 6250 ohm.
1/25 = 250/R1.
R1 = 6250 ohm.
Bhawana Singh said:
1 decade ago
Turn ratio will proportional to square of load then square of resistance in secondary upon primary 2n square.
Rudra said:
1 decade ago
What will be the Phasor diagram for it?
Santosh murkut said:
9 years ago
The transformation ratio is said that N2/N1 = V2/V1 = I1/I2 = K.
Hence,
1) A resistance R1 in primary become K^2 * R1 when transferred to the secondary.
2) A resistance R2 in secondary become R2 / K^2 when transferred to the primary.
Therefore,
R1 = 250 / (10/50)^2 = 6250 ohm.
Hence,
1) A resistance R1 in primary become K^2 * R1 when transferred to the secondary.
2) A resistance R2 in secondary become R2 / K^2 when transferred to the primary.
Therefore,
R1 = 250 / (10/50)^2 = 6250 ohm.
Arjun said:
9 years ago
Reflective resistance = {(1/k^2)*Rload}.
Engr. Mamoona Akbar said:
1 decade ago
t2/t1 = sqrt (load impedance/source impedance).
10/50 = sqrt (250/x).
0.2*0.2 = 250/x.
x = 250/0.04.
x = 6250.
10/50 = sqrt (250/x).
0.2*0.2 = 250/x.
x = 250/0.04.
x = 6250.
Tom said:
8 years ago
Here, n2/n1=r1/r2.
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers