Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 
?
?250
25
6,250
62,500
Discussion:
46 comments Page 3 of 5.
Suresh said:
4 years ago
Voltage of secondary 200v, transformer ration N1:N2= 200:100, X=12 Ohms and Rl = 4 Ohms.
Estimate the RMS value of the primary current I1 and Secondary Current I2 and Estimate the power in watts.
Estimate the RMS value of the primary current I1 and Secondary Current I2 and Estimate the power in watts.
Richa said:
5 years ago
Transformation ratio is N1 (Primary)/N2 (secondary).
Abhishek mohapatra said:
8 years ago
From the basics:
You have to find what resistance on primary will have similar effect as 250 on secondary.
in ideal transformer power associated with primary equals secondary hence V2^2/250 = v1^2/Rreq. similarly V2*I2 =V1*I1. if you know what voltages are related in the same way as a number of turns i.e V2/V1 = N2/N1 then you can easily relate all currents and impedances.
You have to find what resistance on primary will have similar effect as 250 on secondary.
in ideal transformer power associated with primary equals secondary hence V2^2/250 = v1^2/Rreq. similarly V2*I2 =V1*I1. if you know what voltages are related in the same way as a number of turns i.e V2/V1 = N2/N1 then you can easily relate all currents and impedances.
Mahendra chauhan said:
1 decade ago
# given data primary coil turns=50,secondary coil turns=10 & secondary load 250 ohm.
#equation N=secondary coil turns/primary coil turns
(Rpri=reflected in to primary)
Rpri=(1/n)^2*RL
so N =10/50
=0.2
Rpri =(1/0.2)^2*250
=(5)^2*250
=25*250
=6250.
#equation N=secondary coil turns/primary coil turns
(Rpri=reflected in to primary)
Rpri=(1/n)^2*RL
so N =10/50
=0.2
Rpri =(1/0.2)^2*250
=(5)^2*250
=25*250
=6250.
HJHGJK said:
1 decade ago
K=N2/N1
N1=50
N2=10
K=(10/50)=1/5
SECONDARY TO PRIMARY R/K^2
SO 250/(1/5)^2=250*25=6250 OHMS
N1=50
N2=10
K=(10/50)=1/5
SECONDARY TO PRIMARY R/K^2
SO 250/(1/5)^2=250*25=6250 OHMS
Prakash. D. said:
1 decade ago
Turns ratio K= n1/n2= 50/10
K=5,
w.k.t..., R1/R2=K^2
R1=250*25
R1=6250 ohms.
K=5,
w.k.t..., R1/R2=K^2
R1=250*25
R1=6250 ohms.
Chintan said:
1 decade ago
N1=50 , N2=10
Turn ratio K=N2/N1=10/50
K=1/5=0.2
now,R2/R1=K^2
R1=R2/K^2
=250/0.2^2
R1=6250 ohms.
Turn ratio K=N2/N1=10/50
K=1/5=0.2
now,R2/R1=K^2
R1=R2/K^2
=250/0.2^2
R1=6250 ohms.
Siddu said:
1 decade ago
Turns ratio will proportional to square of load then square of resistance in sec/pri 2n square.
Pinnapareddy .sandhya lakshmi said:
1 decade ago
r1=r2/k^2
k=n2/n1=10/50=1/5
r2=250
r1=250/(1/5)^2=6250
r1=6250
k=n2/n1=10/50=1/5
r2=250
r1=250/(1/5)^2=6250
r1=6250
Divij said:
1 decade ago
r1=(n1/n2)^2*r2
WHERE n1=50 , n2=10,r2=250
Ans: 6250
WHERE n1=50 , n2=10,r2=250
Ans: 6250
Post your comments here:
Quick links
Quantitative Aptitude
Verbal (English)
Reasoning
Programming
Interview
Placement Papers