Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 4)
4.
If a transformer has 50 turns in the primary winding and 10 turns in the secondary winding, what is the reflective resistance if the secondary load resistance is 250 
?
?250
25
6,250
62,500
Discussion:
46 comments Page 3 of 5.
Mallikarjun said:
1 decade ago
R2' = r2/(kxk).
r2 = 250 ohms.
k = n2/n1 = 0.2.
(kXk) = 0.04.
R2' = 250/0.04 = 6250.
r2 = 250 ohms.
k = n2/n1 = 0.2.
(kXk) = 0.04.
R2' = 250/0.04 = 6250.
Yatish Ahire said:
1 decade ago
Primary resistance R1 = R2/(K)2.
Here,
K = N2/N1 = 10/50 = 0.2.
Hence,
R' = 250/0.2*0.2 = 6250 Ohm.
Here,
K = N2/N1 = 10/50 = 0.2.
Hence,
R' = 250/0.2*0.2 = 6250 Ohm.
Ododo said:
1 decade ago
Please am confused, turns ratio is it the same as transformer ratio?
I saw that turns ratio = N2/N1, and I still saw that turns ratio = N1/N2, which one is correct with proofs please.
I saw that turns ratio = N2/N1, and I still saw that turns ratio = N1/N2, which one is correct with proofs please.
Engr. Mamoona Akbar said:
1 decade ago
t2/t1 = sqrt (load impedance/source impedance).
10/50 = sqrt (250/x).
0.2*0.2 = 250/x.
x = 250/0.04.
x = 6250.
10/50 = sqrt (250/x).
0.2*0.2 = 250/x.
x = 250/0.04.
x = 6250.
Eshan Mishra said:
1 decade ago
There is difference b/w the terms if simply turn ratio, voltage ratio is mention and transformation ratio is mention in the question.
Eg:- transformation ratio is k, k=[V2/V1=N2/N1=I1/I2].
Simple turn ratio, voltage ratio is equal to 1/k
N1/N2, V1/V2.
And there is one more important relation,
(V2/V1)=Square root(R2/R1).
Eg:- transformation ratio is k, k=[V2/V1=N2/N1=I1/I2].
Simple turn ratio, voltage ratio is equal to 1/k
N1/N2, V1/V2.
And there is one more important relation,
(V2/V1)=Square root(R2/R1).
Arun Kumar Raju C said:
1 decade ago
Ns/Np = sqrt(load resistance/source resistance).
Akash.bhure said:
1 decade ago
Solution:
No.of turns in the primary(N1) = 50.
No.of turns in the secondary(N2) = 10.
Turns ratio(K) = N2/N1 = 10/50 = 0.2.
Secondary load resistance(R2) = 250 Ohm.
Reflective resistance(R1) = R2/K^2.
(R1) = 250/(0.2)^2.
(R1) = 250/0.04 = 6250 ohm's.
No.of turns in the primary(N1) = 50.
No.of turns in the secondary(N2) = 10.
Turns ratio(K) = N2/N1 = 10/50 = 0.2.
Secondary load resistance(R2) = 250 Ohm.
Reflective resistance(R1) = R2/K^2.
(R1) = 250/(0.2)^2.
(R1) = 250/0.04 = 6250 ohm's.
Sandip chhatrola said:
1 decade ago
K^2 = R2/R1.
1/25 = 250/R1.
R1 = 6250 ohm.
1/25 = 250/R1.
R1 = 6250 ohm.
Bhawana Singh said:
1 decade ago
Turn ratio will proportional to square of load then square of resistance in secondary upon primary 2n square.
Rudra said:
1 decade ago
What will be the Phasor diagram for it?
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