Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 12)
12.
In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is
one-fourth the primary current
four times the primary current
equal to the primary current
one-fourth the primary current and equal to the primary current
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 3 of 3.

Suresh said:   1 decade ago
In transformer power is maintained constant i.e., v*i product should be same. , as we increases for n times I decreases for n times vice-versa.

Mohan said:   1 decade ago
Given that V2=(1/4)V1

we know that V2/V1=I1/I2
therefore I1/I2=1/4

So I2=*I1

Aniket said:   1 decade ago
Mangala Prasad Vasu is wrong. In transformer ckt, the current is inversely proportional to the voltage. Because this is an inductive circuit & we all know that in inductive circuit current lags the voltage.
Only for that reason if the primary voltage of the transformer is 4 times the secondary voltage, the secondary current will be 4 times the primary current.

Ramashankar said:   1 decade ago
Suppose the pri.voltage(V1)=100 V
i.e the sec.voltage(V2)=(1/4)*pri.voltage(V1)
=(1/4)*100 =25 V
Actually we know the formula as,
V2/V1=N2/N1=I1/I2=K
i.e Turns ratio(K)=V2/V1=25/100=1/4=0.25
so, I1/I2=K=1/4
or, I2=4*I1 =4*Primary current
i.e sec. current equal to four times the pri. current
i.e we

Azhar Ansari said:   1 decade ago
V1/V2= I2/I1

But V2=.025V1

Vi/0.25Vi= I2/I1
4=I2/I1

4I1= I2

MANGALA PRASAD VASU said:   1 decade ago
Ans:- (B).

Because 'V' is directly proportional to 'i'.

Where 'V' is voltage & 'i' is current flow in ckt.

Zia said:   1 decade ago
Voltage and current are inversely propotional for transformer.


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