Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 12)
12.
In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is
Discussion:
27 comments Page 1 of 3.
Aniket said:
1 decade ago
Mangala Prasad Vasu is wrong. In transformer ckt, the current is inversely proportional to the voltage. Because this is an inductive circuit & we all know that in inductive circuit current lags the voltage.
Only for that reason if the primary voltage of the transformer is 4 times the secondary voltage, the secondary current will be 4 times the primary current.
Only for that reason if the primary voltage of the transformer is 4 times the secondary voltage, the secondary current will be 4 times the primary current.
Ramashankar said:
1 decade ago
Suppose the pri.voltage(V1)=100 V
i.e the sec.voltage(V2)=(1/4)*pri.voltage(V1)
=(1/4)*100 =25 V
Actually we know the formula as,
V2/V1=N2/N1=I1/I2=K
i.e Turns ratio(K)=V2/V1=25/100=1/4=0.25
so, I1/I2=K=1/4
or, I2=4*I1 =4*Primary current
i.e sec. current equal to four times the pri. current
i.e we
i.e the sec.voltage(V2)=(1/4)*pri.voltage(V1)
=(1/4)*100 =25 V
Actually we know the formula as,
V2/V1=N2/N1=I1/I2=K
i.e Turns ratio(K)=V2/V1=25/100=1/4=0.25
so, I1/I2=K=1/4
or, I2=4*I1 =4*Primary current
i.e sec. current equal to four times the pri. current
i.e we
Subhransu said:
1 decade ago
V is directly proportional I in case of a straight conductor according to ohm law. But it is not applicable in inductive circuit as I lags V by 90 Deg. We all know that P=VI. To maintain power constant if V will increase then I have to decrease.
Sandeep kumar yadav said:
1 decade ago
According to condition ,v2=1/4*v1 for getting the value of v1=4v2 by using condition.
By formula,
v2/v1=i1/i2 v2/4v2=i1/i2 by solving this we get secondary current 4 times of primary current.
By formula,
v2/v1=i1/i2 v2/4v2=i1/i2 by solving this we get secondary current 4 times of primary current.
Srinivas said:
1 decade ago
To make transformer power is constant the current increases with decreasing the voltage for step down transformers. And it is decreases with increasing the voltage for step up transformers.
N Suneel Kumar said:
8 years ago
In Any transformer input power = Output power.
i.e. Input(V*I) = Ouput(V*I).
- In case of Step down transformer, Voltage comes down and Current increases
same case these is.
i.e. Input(V*I) = Ouput(V*I).
- In case of Step down transformer, Voltage comes down and Current increases
same case these is.
(1)
Venki.N said:
1 decade ago
The main thing here is, in the secondary coil the voltage decreased and current increased because current is inversely proportional to voltage in a transformer.
Suresh said:
1 decade ago
In transformer power is maintained constant i.e., v*i product should be same. , as we increases for n times I decreases for n times vice-versa.
RAVI RATHOD said:
1 decade ago
Take v2 = 1/4v1.
So, we have v2/v1 = n2/n1 = i1/i2.
v2/v1 = i1/i2.
Instead of v2 = 1/4v1.
1/4v1/v1 = i1/i2.
1/4 = i1/i2.
i2 = 4i1.
So, we have v2/v1 = n2/n1 = i1/i2.
v2/v1 = i1/i2.
Instead of v2 = 1/4v1.
1/4v1/v1 = i1/i2.
1/4 = i1/i2.
i2 = 4i1.
Jagadish said:
9 years ago
We know V2/V1 = I1/I2.
THEN I2 = V1 * I1/V2.
IN THIS QUESTION, secondary voltage is given 1/4 of V1 then it becomes.
I2 = 4 * I1.
THEN I2 = V1 * I1/V2.
IN THIS QUESTION, secondary voltage is given 1/4 of V1 then it becomes.
I2 = 4 * I1.
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