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Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 12)
Transformers
12.
In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is
one-fourth the primary current
four times the primary current
equal to the primary current
one-fourth the primary current and equal to the primary current
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 2 of 3.
MANGALA PRASAD VASU said:   1 decade ago
Ans:- (B).

Because 'V' is directly proportional to 'i'.

Where 'V' is voltage & 'i' is current flow in ckt.
Murali said:   10 years ago
Answer option B is right because in the transformer power is constant.

Therefore input power = output power.
(1)
Nakul chandran said:   8 years ago
v2=v1/4....v1/v2=4=i2/i1....or i2=4*i1,......................secondary current 4 times the primary current.
(2)
Dharam Pal Moudgil said:   1 decade ago
I1/i2 = V2/v1.

Now V2 = 1/4*v1.

So I1/i2 = V1/4/v1.

I1/I2=1/4.

Or I1=I2/4.

And 4*I1 = I2, answer.
Akash said:   1 decade ago
Voltage (V) and current (I) are inversely proportional to each other in a transformer circuit.
Anisha said:   7 years ago
In the case of a step-down transformer, the voltage comes down and current increase same Case.
(1)
Sanjiv ku.jagdev said:   1 decade ago
Voltage and current are inversely propotional for transformer.
in a transformer v2/v1=i1/i2...
Rajee said:   1 decade ago
N2/N1=V2/V1=I1/I2. Eqn (1).

Given V2=V1/4.

(V1/4) /V1=I1/I2.

V1/4V1=I1/I2.

4I1=I2.
Prasad said:   1 decade ago
v2/v1 = i1/i2.
(1/4)/1 = i1/i2.
1/4 = i1/i2.

Therefore i2 = Secondary current = 4i1.
Mohan said:   1 decade ago
Given that V2=(1/4)V1

we know that V2/V1=I1/I2
therefore I1/I2=1/4

So I2=*I1
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