Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 12)
12.
In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is
one-fourth the primary current
four times the primary current
equal to the primary current
one-fourth the primary current and equal to the primary current
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 1 of 3.

Anisha said:   7 years ago
In the case of a step-down transformer, the voltage comes down and current increase same Case.
(1)

Nakul chandran said:   8 years ago
v2=v1/4....v1/v2=4=i2/i1....or i2=4*i1,......................secondary current 4 times the primary current.
(2)

N Suneel Kumar said:   8 years ago
In Any transformer input power = Output power.

i.e. Input(V*I) = Ouput(V*I).

- In case of Step down transformer, Voltage comes down and Current increases
same case these is.
(1)

Swathi reddy said:   8 years ago
V2/v1= i1/i2,
V1=(1/4)v1.
((1/4)v1)/v1=i1/i2.
4(i1/i2).

Jagadish said:   9 years ago
We know V2/V1 = I1/I2.
THEN I2 = V1 * I1/V2.

IN THIS QUESTION, secondary voltage is given 1/4 of V1 then it becomes.

I2 = 4 * I1.

Murali said:   10 years ago
Answer option B is right because in the transformer power is constant.

Therefore input power = output power.
(1)

Dileep kumar chaurasia said:   10 years ago
I is increased v is decreased because V=1/I.

Venki.N said:   1 decade ago
The main thing here is, in the secondary coil the voltage decreased and current increased because current is inversely proportional to voltage in a transformer.

RAVI RATHOD said:   1 decade ago
Take v2 = 1/4v1.

So, we have v2/v1 = n2/n1 = i1/i2.

v2/v1 = i1/i2.

Instead of v2 = 1/4v1.

1/4v1/v1 = i1/i2.
1/4 = i1/i2.
i2 = 4i1.

Dharam Pal Moudgil said:   1 decade ago
I1/i2 = V2/v1.

Now V2 = 1/4*v1.

So I1/i2 = V1/4/v1.

I1/I2=1/4.

Or I1=I2/4.

And 4*I1 = I2, answer.


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