Electrical Engineering - Transformers - Discussion

Discussion Forum : Transformers - General Questions (Q.No. 12)
12.
In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is
one-fourth the primary current
four times the primary current
equal to the primary current
one-fourth the primary current and equal to the primary current
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
27 comments Page 2 of 3.

Prasad said:   1 decade ago
v2/v1 = i1/i2.
(1/4)/1 = i1/i2.
1/4 = i1/i2.

Therefore i2 = Secondary current = 4i1.

Sandeep kumar yadav said:   1 decade ago
According to condition ,v2=1/4*v1 for getting the value of v1=4v2 by using condition.

By formula,

v2/v1=i1/i2 v2/4v2=i1/i2 by solving this we get secondary current 4 times of primary current.

Subhransu said:   1 decade ago
V is directly proportional I in case of a straight conductor according to ohm law. But it is not applicable in inductive circuit as I lags V by 90 Deg. We all know that P=VI. To maintain power constant if V will increase then I have to decrease.

Akash said:   1 decade ago
Voltage (V) and current (I) are inversely proportional to each other in a transformer circuit.

Rajee said:   1 decade ago
N2/N1=V2/V1=I1/I2. Eqn (1).

Given V2=V1/4.

(V1/4) /V1=I1/I2.

V1/4V1=I1/I2.

4I1=I2.

Shahed said:   1 decade ago
Ip/Is=1/4Vp whole divided by Vp
Is=4Ip

Sanjiv ku.jagdev said:   1 decade ago
Voltage and current are inversely propotional for transformer.
in a transformer v2/v1=i1/i2...

Sita said:   1 decade ago
E2/E1=I1/I2
(1/4)E1/E1=I1/I2
I2=4I1

Aparna said:   1 decade ago
Thanks Aniket.

Suresh said:   1 decade ago
In transformer power is maintained constant i.e., v*i product should be same. , as we increases for n times I decreases for n times vice-versa.


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