Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 12)
12.
In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is
Discussion:
27 comments Page 2 of 3.
Dharam Pal Moudgil said:
1 decade ago
I1/i2 = V2/v1.
Now V2 = 1/4*v1.
So I1/i2 = V1/4/v1.
I1/I2=1/4.
Or I1=I2/4.
And 4*I1 = I2, answer.
Now V2 = 1/4*v1.
So I1/i2 = V1/4/v1.
I1/I2=1/4.
Or I1=I2/4.
And 4*I1 = I2, answer.
Prasad said:
1 decade ago
v2/v1 = i1/i2.
(1/4)/1 = i1/i2.
1/4 = i1/i2.
Therefore i2 = Secondary current = 4i1.
(1/4)/1 = i1/i2.
1/4 = i1/i2.
Therefore i2 = Secondary current = 4i1.
Sandeep kumar yadav said:
1 decade ago
According to condition ,v2=1/4*v1 for getting the value of v1=4v2 by using condition.
By formula,
v2/v1=i1/i2 v2/4v2=i1/i2 by solving this we get secondary current 4 times of primary current.
By formula,
v2/v1=i1/i2 v2/4v2=i1/i2 by solving this we get secondary current 4 times of primary current.
Subhransu said:
1 decade ago
V is directly proportional I in case of a straight conductor according to ohm law. But it is not applicable in inductive circuit as I lags V by 90 Deg. We all know that P=VI. To maintain power constant if V will increase then I have to decrease.
Srinivas said:
1 decade ago
To make transformer power is constant the current increases with decreasing the voltage for step down transformers. And it is decreases with increasing the voltage for step up transformers.
Rajee said:
1 decade ago
N2/N1=V2/V1=I1/I2. Eqn (1).
Given V2=V1/4.
(V1/4) /V1=I1/I2.
V1/4V1=I1/I2.
4I1=I2.
Given V2=V1/4.
(V1/4) /V1=I1/I2.
V1/4V1=I1/I2.
4I1=I2.
Shahed said:
1 decade ago
Ip/Is=1/4Vp whole divided by Vp
Is=4Ip
Is=4Ip
Sanjiv ku.jagdev said:
1 decade ago
Voltage and current are inversely propotional for transformer.
in a transformer v2/v1=i1/i2...
in a transformer v2/v1=i1/i2...
Sita said:
1 decade ago
E2/E1=I1/I2
(1/4)E1/E1=I1/I2
I2=4I1
(1/4)E1/E1=I1/I2
I2=4I1
Aparna said:
1 decade ago
Thanks Aniket.
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