Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 12)
12.
In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is
Discussion:
27 comments Page 3 of 3.
Dileep kumar chaurasia said:
1 decade ago
I is increased v is decreased because V=1/I.
Murali said:
10 years ago
Answer option B is right because in the transformer power is constant.
Therefore input power = output power.
Therefore input power = output power.
(1)
Jagadish said:
9 years ago
We know V2/V1 = I1/I2.
THEN I2 = V1 * I1/V2.
IN THIS QUESTION, secondary voltage is given 1/4 of V1 then it becomes.
I2 = 4 * I1.
THEN I2 = V1 * I1/V2.
IN THIS QUESTION, secondary voltage is given 1/4 of V1 then it becomes.
I2 = 4 * I1.
Swathi reddy said:
8 years ago
V2/v1= i1/i2,
V1=(1/4)v1.
((1/4)v1)/v1=i1/i2.
4(i1/i2).
V1=(1/4)v1.
((1/4)v1)/v1=i1/i2.
4(i1/i2).
N Suneel Kumar said:
8 years ago
In Any transformer input power = Output power.
i.e. Input(V*I) = Ouput(V*I).
- In case of Step down transformer, Voltage comes down and Current increases
same case these is.
i.e. Input(V*I) = Ouput(V*I).
- In case of Step down transformer, Voltage comes down and Current increases
same case these is.
(1)
Nakul chandran said:
8 years ago
v2=v1/4....v1/v2=4=i2/i1....or i2=4*i1,......................secondary current 4 times the primary current.
(2)
Anisha said:
7 years ago
In the case of a step-down transformer, the voltage comes down and current increase same Case.
(1)
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