Electrical Engineering - Transformers - Discussion
Discussion Forum : Transformers - General Questions (Q.No. 12)
12.
In a certain loaded transformer, the secondary voltage is one-fourth the primary voltage. The secondary current is
Discussion:
27 comments Page 2 of 3.
Sanjiv ku.jagdev said:
1 decade ago
Voltage and current are inversely propotional for transformer.
in a transformer v2/v1=i1/i2...
in a transformer v2/v1=i1/i2...
Shahed said:
1 decade ago
Ip/Is=1/4Vp whole divided by Vp
Is=4Ip
Is=4Ip
Rajee said:
1 decade ago
N2/N1=V2/V1=I1/I2. Eqn (1).
Given V2=V1/4.
(V1/4) /V1=I1/I2.
V1/4V1=I1/I2.
4I1=I2.
Given V2=V1/4.
(V1/4) /V1=I1/I2.
V1/4V1=I1/I2.
4I1=I2.
Akash said:
1 decade ago
Voltage (V) and current (I) are inversely proportional to each other in a transformer circuit.
Subhransu said:
1 decade ago
V is directly proportional I in case of a straight conductor according to ohm law. But it is not applicable in inductive circuit as I lags V by 90 Deg. We all know that P=VI. To maintain power constant if V will increase then I have to decrease.
Sandeep kumar yadav said:
1 decade ago
According to condition ,v2=1/4*v1 for getting the value of v1=4v2 by using condition.
By formula,
v2/v1=i1/i2 v2/4v2=i1/i2 by solving this we get secondary current 4 times of primary current.
By formula,
v2/v1=i1/i2 v2/4v2=i1/i2 by solving this we get secondary current 4 times of primary current.
Prasad said:
1 decade ago
v2/v1 = i1/i2.
(1/4)/1 = i1/i2.
1/4 = i1/i2.
Therefore i2 = Secondary current = 4i1.
(1/4)/1 = i1/i2.
1/4 = i1/i2.
Therefore i2 = Secondary current = 4i1.
Dharam Pal Moudgil said:
1 decade ago
I1/i2 = V2/v1.
Now V2 = 1/4*v1.
So I1/i2 = V1/4/v1.
I1/I2=1/4.
Or I1=I2/4.
And 4*I1 = I2, answer.
Now V2 = 1/4*v1.
So I1/i2 = V1/4/v1.
I1/I2=1/4.
Or I1=I2/4.
And 4*I1 = I2, answer.
RAVI RATHOD said:
1 decade ago
Take v2 = 1/4v1.
So, we have v2/v1 = n2/n1 = i1/i2.
v2/v1 = i1/i2.
Instead of v2 = 1/4v1.
1/4v1/v1 = i1/i2.
1/4 = i1/i2.
i2 = 4i1.
So, we have v2/v1 = n2/n1 = i1/i2.
v2/v1 = i1/i2.
Instead of v2 = 1/4v1.
1/4v1/v1 = i1/i2.
1/4 = i1/i2.
i2 = 4i1.
Venki.N said:
1 decade ago
The main thing here is, in the secondary coil the voltage decreased and current increased because current is inversely proportional to voltage in a transformer.
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