Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 4)
4.
In a certain three-wire Y-connected generator, the phase voltages are 2 kV. The magnitudes of the line voltages are
Discussion:
32 comments Page 3 of 4.
Puni said:
1 decade ago
What about in delta conn?
Ajakpogha Ferdinand O. said:
1 decade ago
Vl=root3*Vph
= 1.7320*2000
= 3,464.1016V
where Vl=Line Voltage
Vph=Phase Voltage
= 1.7320*2000
= 3,464.1016V
where Vl=Line Voltage
Vph=Phase Voltage
Gajendra Singh said:
1 decade ago
WKT
V(line)=root3* V(Phase)
i.e.
V(line)=root3*2100
=3464.10volts
V(line)=root3* V(Phase)
i.e.
V(line)=root3*2100
=3464.10volts
Manohar kr. gaur said:
1 decade ago
We know,
vl=root3*vph
then,vl=2000*1.732
=3464.10 volts
vl=root3*vph
then,vl=2000*1.732
=3464.10 volts
Shan said:
1 decade ago
For Y(Star connection): Line Voltage=1.732* phase Voltage
For Delta connection: Line Voltage= Phase Voltage.
Accordingly,
=2000*1.732
=3464.10 volts...
For Delta connection: Line Voltage= Phase Voltage.
Accordingly,
=2000*1.732
=3464.10 volts...
Vibha said:
1 decade ago
vl=root 3 of vph
Siddu said:
1 decade ago
In star connection line voltage equal to root 3 times of the phase voltage so answer is 2000*1.732=3464.
Saravana said:
1 decade ago
Line voltage = root three times of phase voltage
=1.732*2000
=3,464volts
=1.732*2000
=3,464volts
Lavanya said:
1 decade ago
Line voltage = (root 3 times) of phase voltage.
Bablu said:
1 decade ago
Line voltage=root3 times of phase voltage.
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