Electrical Engineering - Three-Phase Systems in Power Applications - Discussion

Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 4)
4.
In a certain three-wire Y-connected generator, the phase voltages are 2 kV. The magnitudes of the line voltages are
2,000 V
6,000 V
666 V
3,464 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
32 comments Page 1 of 4.

Himanshu Dakre said:   7 years ago
In star connected systems,
Line voltage is √3 phase voltage .
i.e. = 2000 * √3 .
Hence 3464 is the answer.
(8)

Sunil said:   7 years ago
VL =1.732 Voh.
IL=Iph.
(3)

Hussain nuhaadh said:   8 years ago
1.7321 * 2000 = 3464.2.
(1)

Siddu said:   8 years ago
Here, √ 3 * phase voltage.
(1)

Musahak khan said:   9 years ago
Phase voltage = 2000v.
So,line voltage = root3 * 2000 volt,
= 3464volt.

Musahak khan said:   9 years ago
Phase voltage = 2000v.
So,line voltage = root3 * 2000 volt,
= 3464volt.

Musahak khan said:   9 years ago
Phase voltage = 2000v.
So,line voltage = root3 * 2000 volt,
= 3464volt.

KARNA said:   9 years ago
In star connection line current = phase current,

Line voltage = 1/3 phase voltage.

And in delta connection line voltage = phase voltage,

Line current = root 3 phase voltage.

So, how is the answer 'd' correct?

By this star connection, the answer is 'c'. It's the right answer.

RANJAN GUPTA said:   9 years ago
2kv = vph root three * vph.
1.73 * 2000.
= 3460 VOLT.

B.Teja Sri said:   9 years ago
In Three phase system star connection vl = root(3)Vph.

Given,

2kv = vph Where root(3) = 1.732.

vl = 2000 * 1.732 =3464.


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