Electrical Engineering - Three-Phase Systems in Power Applications - Discussion

Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 4)
4.
In a certain three-wire Y-connected generator, the phase voltages are 2 kV. The magnitudes of the line voltages are
2,000 V
6,000 V
666 V
3,464 V
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
32 comments Page 2 of 4.

Karthi said:   9 years ago
In a three phase system star connection line voltage is root of three. So 2000kv multiply with root of three.

In delta connection: Line current = Square root of 3 multiplied to Phase current while Line voltage = Phase voltage.

Sandeep wasnik said:   1 decade ago
vl = root three*vph.
= 1.73*2kv.
= 1.73*2000.
= 3460 volt.

Rajiv gandhi said:   1 decade ago
In a three phase system star connection line voltage is root of three so 2000kv multiply with root of three. It is right answer.

ARUNPANDIYAN M said:   1 decade ago
VL = 1.732*VPH.
VL = 1.732*2000.
VL = 3464.

Vishal said:   1 decade ago
Why come 1.732 please answer I m not understand?

Saleem pasha said:   1 decade ago
Line voltage = root3 times phase voltage.

Sanjay verma said:   1 decade ago
Line voltage = root three phase voltage, so 1.732*2000 = and is 3464.

VARADHA SIT said:   1 decade ago
VL= ROOT 3 INTO VP.

VP = 2KV = 2000V.

ROOT3 = 1.732.

VL = 1.732 [2000] = 3464.

Venkidu said:   1 decade ago
VL is equal to the Vph.

VL = root3*Vph.

= 1.732*2000.

= 3464.1016V.

Chado said:   1 decade ago
In wye connection: Line voltage = square root of 3 multiplied to Phase voltage while Line current = Phase current

In delta connection: Line current = square root of 3 multiplied to Phase current while Line voltage = Phase voltage


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