Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 12)
12.
Compare the total copper cross sections in terms of current-carrying capacity for a single-phase and a three-phase 120 V system with effective load resistance of 15 
.
.Discussion:
20 comments Page 1 of 2.
Ogunjimi Biliaminu said:
2 years ago
For, 3phse p = vSq/R = 120sq/15 = 960watts.
960 = line current x line voltage x cosine θ x 1.732.
Line current = 960/166.272 = 5.77A;
For a single phase l = V/R. 120/15 = 8amps.
960 = line current x line voltage x cosine θ x 1.732.
Line current = 960/166.272 = 5.77A;
For a single phase l = V/R. 120/15 = 8amps.
Sai said:
3 years ago
I am not understanding this. Please explain me in detail.
(2)
N.D. said:
5 years ago
In the three-phase system, one phase will carry current while the remaining two phases will act as a return so current required per phase will be proportional to 8A.
In the single-phase system two-conductor will be required per phase so so current required per phase will be proportional to 16A.
In the single-phase system two-conductor will be required per phase so so current required per phase will be proportional to 16A.
(1)
Vinod said:
7 years ago
In three phase balance system, the current through neutral must be zero. How 8A will flow?
Prabha said:
7 years ago
Single phase means ph and neutral how would be taken neutral as a phase?
Please explain it, I didn't understand.
Please explain it, I didn't understand.
Doni said:
8 years ago
Please give me the clear explanation of the answer!
Rohini G said:
9 years ago
Not getting this, please explain it again.
Kishna said:
9 years ago
How? Please explain it clearly.
Suyash kumar chaurasiya said:
9 years ago
@Ayush.
If we have a single phase power then for finding the three phase power we are simply multiply by 3*1 phase power so how can you say that if 3 phase current is i then one phase current is 2*i, explain it?
If we have a single phase power then for finding the three phase power we are simply multiply by 3*1 phase power so how can you say that if 3 phase current is i then one phase current is 2*i, explain it?
(2)
Ayush Kumar said:
9 years ago
Since for 3phase current = 120/15 = 8A & for single phase current = 2 * phase current because in this case two wire remains & therefore required single phase current = 2 * 8 = 16A.
(2)
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