Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 12)
12.
Compare the total copper cross sections in terms of current-carrying capacity for a single-phase and a three-phase 120 V system with effective load resistance of 15 
.
.Discussion:
20 comments Page 2 of 2.
Panksa said:
9 years ago
Please give the clear explanation.
Gopalan said:
9 years ago
I am not clear with the question and answer. Please help me to understand.
Rasu said:
10 years ago
I cannot understand sir. I need some more clear explanation.
Preeti verma said:
10 years ago
Logically explained.
Galib said:
10 years ago
Very nice explanation.
Azhagar said:
1 decade ago
@Black-menace.
3ph curr = 8A which is for per phase. If 1 phase (2 wires), So 2*8 = 16.
3ph curr = 8A which is for per phase. If 1 phase (2 wires), So 2*8 = 16.
Black_menace said:
1 decade ago
Why for single phase=2*3phase current?
Manash said:
1 decade ago
The proper choice of a resister to determine a wanted current flow in a particular circuit is knows as effective resistance.
Krishan Kant said:
1 decade ago
What is the meaning of effective load ?
Is it in star or delta and the factor must be sqrt (3).
Is it in star or delta and the factor must be sqrt (3).
Vijay said:
1 decade ago
i=v/r
=120/15
=8a
but in single phase=2*3phase current
=2*8
=16a
=120/15
=8a
but in single phase=2*3phase current
=2*8
=16a
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