Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 9)
9.
A two-phase generator is connected to two 90
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?

Discussion:
63 comments Page 4 of 7.
Nitin said:
3 years ago
The 2 resistors are connected in parallel or series, the result (I) may vary accordingly.
Parth Vaghela said:
3 years ago
The circuit will be balanced due to the same amount of load on both phases and so the current through the neutral wire must be zero.
Subhankar said:
1 decade ago
The guys saying that for balance load no current follows through the neutral should think that neutral is common here. So answer 2.66.
Prashant said:
1 decade ago
Can you give the circuit diagrm? or solve the problem.
Vikram said:
1 decade ago
Please explaination of this answer.
Sukhvinder singh said:
1 decade ago
This is wrong the answer is c. The neutral will have sum of both the line currents.
Indradeo kumar said:
1 decade ago
Please give the explaination of this answer.
Ajeet shukla said:
1 decade ago
@Sukvinder please explain in detail how you get this?
Mirdul said:
1 decade ago
Please give me formula
Durga prasad said:
1 decade ago
Wrong answer...correct answer is (1.88) I in neutral= (120/90)+((120/90)<90)=1.88 magnitude
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