Electrical Engineering - Three-Phase Systems in Power Applications - Discussion

Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 9)
9.
A two-phase generator is connected to two 90 load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?
1.33 A
1.88 A
2.66 A
1.77 A
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
63 comments Page 4 of 7.

Nitin said:   3 years ago
The 2 resistors are connected in parallel or series, the result (I) may vary accordingly.

Parth Vaghela said:   3 years ago
The circuit will be balanced due to the same amount of load on both phases and so the current through the neutral wire must be zero.

Subhankar said:   1 decade ago
The guys saying that for balance load no current follows through the neutral should think that neutral is common here. So answer 2.66.

Prashant said:   1 decade ago
Can you give the circuit diagrm? or solve the problem.

Vikram said:   1 decade ago
Please explaination of this answer.

Sukhvinder singh said:   1 decade ago
This is wrong the answer is c. The neutral will have sum of both the line currents.

Indradeo kumar said:   1 decade ago
Please give the explaination of this answer.

Ajeet shukla said:   1 decade ago
@Sukvinder please explain in detail how you get this?

Mirdul said:   1 decade ago
Please give me formula

Durga prasad said:   1 decade ago
Wrong answer...correct answer is (1.88) I in neutral= (120/90)+((120/90)<90)=1.88 magnitude


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