Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 9)
9.
A two-phase generator is connected to two 90 
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?Discussion:
63 comments Page 1 of 7.
Sandeep said:
1 decade ago
Can you give the circuit diagrm?
Prashant said:
1 decade ago
Can you give the circuit diagrm? or solve the problem.
Vikram said:
1 decade ago
Please explaination of this answer.
Sukhvinder singh said:
1 decade ago
This is wrong the answer is c. The neutral will have sum of both the line currents.
Indradeo kumar said:
1 decade ago
Please give the explaination of this answer.
Ajeet shukla said:
1 decade ago
@Sukvinder please explain in detail how you get this?
Mirdul said:
1 decade ago
Please give me formula
Durga prasad said:
1 decade ago
Wrong answer...correct answer is (1.88) I in neutral= (120/90)+((120/90)<90)=1.88 magnitude
K.n.lakshmi said:
1 decade ago
I=V/R
2 RESISTORS ARE THERE.
NEUTRAL CURRENT=120/9+120/9==2.66
I THINK THE ANSWER IS C=2.66A
2 RESISTORS ARE THERE.
NEUTRAL CURRENT=120/9+120/9==2.66
I THINK THE ANSWER IS C=2.66A
Prerna said:
1 decade ago
The answer should be 1.88 Amp. The current at any instant (also called as instantenous current) flowing through each phase and through each load ckt. is Inst(1) = 1.33 Amp. This same current at any instant will flow through th neutral wire. However the current in a.c circuit is expressed in terms of its r.m.s value and the relationship between these currents is Irms = sqrt. 2 * Inst = 1.141 * 1.33 = 1.88 A. Hence the answer should be option B
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