Electrical Engineering - Three-Phase Systems in Power Applications - Discussion

Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 9)
9.
A two-phase generator is connected to two 90 load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?
1.33 A
1.88 A
2.66 A
1.77 A
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
63 comments Page 1 of 7.

Ashfaq Sarwar said:   7 years ago
Correct answer is D:

as Va and Vb are 90 degree apart so;

Va=120<0; ---> polar form
Vb=120<90 ---> polar form.

Lets convert it into rectangular form
Va=120*(cos(0)+jsin(0)).
Va=120;
Vb=120*(cos(90)+jsin(90)).
Vb=j120;.

Now calculating current;
Ia= 120/90;
Ia=1.33;
Ib= j120/90;
Ib=j1.33;.

Total Current=Ia+Ib.
I=1.33+j1.33;
Converting back to polar form.
magnitude=
I= √((1.33)^2+(j1.33)^2).
I=1.76;.
θ=tan inv(1.33/1.33);.
θ=45.

So;
I=1.76<45;
Thanks; Hope it works
(11)

Ivanha said:   6 years ago
Given 3 phase currents; A, B, and C, we say that neutral current is equal to (A^2 + B^2 + C^2)-(AB + BC + CA).

Therefore, given 2 phase currents, A and B, netrual current is equal to (A^2 + B^2)-(AB)
Ip=Vp/Rp ==>> 120/90 = 1.3333A.

Since A=B, then neutral current is equal to (A^4)-(A^2) = A^2.
1.3333^2 = 1.7777.
(8)

Shahid said:   4 years ago
There are two loads, hence the current passes through both the resistors and common Neutral

V= 120V each phase
1/R= 1/90+1/90=2/90= 1/45
R=45Ω

V = IR.
I = V/R.

Hence neutral Current
I=V/R1+V/R2
=(120/90)+(120/90).

I = 1.33+1.33 = 2.66 amp.
Or I = 120/45= 2.66 Amp.

Whereas Generator is two-phase so the Neutral Current is
IN = I * (difference in Phase angle/Total +ve angle)
the difference in phase=120.

Total angle start from zero then high and zero=180
= 2.66 * (120/180).
(7)

Ayush Kumar said:   9 years ago
It is simple question since, two phase generator is connected to two load resistor therefore resistance = 90 * 90 = 8100 & total voltage = 120 * 120 = 14400.

Therefore required current through common neutral line is = 14400/8100 = 1.77A.
(3)

Shivaraj said:   8 years ago
Give me the correct explanation!
(2)

Amjad moawia said:   10 years ago
There is the two phase.

120*120 = 14400 volt.

90*90 = 8100 ohm.

Hence current (i) = v/r.

= 14400/8100 = 1.77 amp.
(2)

Shankar yadav said:   9 years ago
V = IR.
Total resistance of two resistors(is parallel) is:

45ohms,
Voltage is 120v,
Current is =120/45,
Current is 2.66 amps.
(1)

Parth Vaghela said:   3 years ago
The circuit will be balanced due to the same amount of load on both phases and so the current through the neutral wire must be zero.
(1)

KeerthiRaj said:   1 decade ago
@Mr Parveen Kumar and Mr Sandeep Wasnik:

Although your ideas were wrong, but I think you people even don't know how to calculate phase to phase voltage, if you don't know please keep quiet, don't post wrong things.

Sayed Tousif Pasha said:   1 decade ago
Whether the load is in series or parallel.


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