Electrical Engineering - Three-Phase Systems in Power Applications - Discussion
Discussion Forum : Three-Phase Systems in Power Applications - General Questions (Q.No. 9)
9.
A two-phase generator is connected to two 90 
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?
load resistors. Each coil generates 120 V ac. A common neutral line exists. How much current flows through the common neutral line?Discussion:
63 comments Page 7 of 7.
RUPESH S BORADE said:
1 decade ago
If 2 resistance are in parallel then.
(90*90)/180 = 45.
I = V/R.
I = 120/45.
I = 2.66.
That's answer is C.
(90*90)/180 = 45.
I = V/R.
I = 120/45.
I = 2.66.
That's answer is C.
Saheb said:
1 decade ago
Suppose, open delta connection neutral i = i/3^1/2.
Here, i = (120/90) + (120/90) = 2.66 A.
Neutral i = 2.66/3^1/2 = 1.54~1.77 A.
Here, i = (120/90) + (120/90) = 2.66 A.
Neutral i = 2.66/3^1/2 = 1.54~1.77 A.
Yousuf Hasan said:
1 decade ago
Circuit diagram is must, you don't know how the two resistor are connected? (series or parallel). For the line current you should know the equivalent resistance seen by the line.
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