# Electrical Engineering - Series-Parallel Circuits - Discussion

### Discussion :: Series-Parallel Circuits - General Questions (Q.No.6)

6.

Three 10 k resistors are connected in series. A 20 k resistor is connected in parallel across one of the 10 k resistors. The voltage source is 24 V. The total current in the circuit is

 [A]. 900 A [B]. 9 mA [C]. 90 mA [D]. 800 A

Explanation:

No answer description available for this question.

 Ramu said: (Jun 10, 2011) (30+20+10)/0.066 = 900

 Nadarajan V said: (Jun 22, 2011) 20k ohm + ((20*10)/(20+10)) = 26.67k ohm V= IR => I= V/R => I= 24V/26.67k ohm => I= 24V/26670ohm => I= 0.0008998875A => I= 899.8875 micro Amps so 900 micro Amps is the correct answer.

 Anand said: (Jul 27, 2011) Nice Explanation Nadarajan...

 Uday said: (Sep 23, 2011) [{(20*10)/30}+10+10]=80/3 then v=24v now i=v/r=24/(80/3)*1/1000=(72/80)1/*1000=0.9/1000=0.0009=900microA

 Shailaja said: (Jan 16, 2012) 10K 10K 10K ------^^^^^-----^^^^-----^^^^------ | | | | | | | > | | >20K OHM 24 V | > | | | | ------------------------------------ Is this circuit diagram is correct?

 Pukhraj said: (Mar 17, 2012) Thanks nadarajan.

 Arun said: (Dec 12, 2012) R=20+(20*10)/30=26.67. I=V/R=24/26.67=.899 mA= 900uA.

 Trupti said: (Jun 23, 2015) V = IR. I = V/R. R1 = R2 = R3 = 10 kohm. One 20 kohm resistor is parallel with one of the 10 kohm resistor. So say R4 = 20 kohm parallel with R1. Total resistance= (R1*R4/R1+R4)+R2+R3 = 26666.66 ohms. I = 24/26666.66 = 900 uA.

 Ali said: (Sep 10, 2015) R = R1+R2+R3. R = 10+10+6.66666 = 26.66666 K ohm. 1/R3 = 1/10+1/20. R3 = 6.666666. I =V/R = 24/26666.67 = 90 m A.

 Aamir said: (Nov 20, 2015) In the given question, R1, R2 and R3 are in series and R4 is in parallel with any one. So for example R4||R3. Now R1 and R2 in series 10+10 = 20 k and from R3 and R4 = 6.66 k, which is now in series with R1 and R2. Then Rt is 26.66 k. To find I = v/r. I = 24v/26.66k = 0.900 mA = 900 uA.

 Pappish said: (Feb 4, 2016) Three 10k in series but one 10k in parallel with 20k = 10*20/30 = 6.66 k + 20 k = 26.66 k. I = 24/26.66 k = 900 uA.

 Mayur Shankariya said: (Jun 14, 2016) @Uday. Thanks for the explanation.

 Shashikant Chiranjivi said: (Feb 7, 2017) Thanks @Arun.

 Sourabh said: (Feb 7, 2017) Nice explanations, thank you all.

 Sanjay said: (Mar 3, 2017) Thanks for explanation @Trupti.

 Rion said: (Mar 29, 2017) Here, R = 20k||10k + 20k. I = 24/R.

 Thiyanesh said: (Jul 9, 2017) Thanks @Ali.

 Rakesh said: (Feb 22, 2018) How to solve it? please explain me.

 Anomii said: (Aug 14, 2018) Good explanation. Thanks.

 Coolman said: (Oct 17, 2019) Ohms Law I = V/R. So, As question said 3 resistors in series with each value 10K and second question said 20K resistor parallel connected with one of 10K resistor. Therefore, we can say total resistance is = R1+R2+(R3//20K), hence R3 resistor parallel connected with 20K, = 10K + 10K+((10K*20K) / (10K+20K). = 26.67K ohm. So now the total current is, I = V/R. = 24V / 26.67K. = 900 micro ampere.