Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 6)
6.
Three 10 k
resistors are connected in series. A 20 k
resistor is connected in parallel across one of the 10 k
resistors. The voltage source is 24 V. The total current in the circuit is



Discussion:
23 comments Page 3 of 3.
Anand said:
1 decade ago
Nice Explanation Nadarajan...
Nadarajan V said:
1 decade ago
20k ohm + ((20*10)/(20+10)) = 26.67k ohm
V= IR => I= V/R
=> I= 24V/26.67k ohm
=> I= 24V/26670ohm
=> I= 0.0008998875A
=> I= 899.8875 micro Amps
so 900 micro Amps is the correct answer.
V= IR => I= V/R
=> I= 24V/26.67k ohm
=> I= 24V/26670ohm
=> I= 0.0008998875A
=> I= 899.8875 micro Amps
so 900 micro Amps is the correct answer.
Ramu said:
1 decade ago
(30+20+10)/0.066 = 900
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