Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 6)
6.
Three 10 k
resistors are connected in series. A 20 k resistor is connected in parallel across one of the 10 k resistors. The voltage source is 24 V. The total current in the circuit is
resistors are connected in series. A 20 k resistor is connected in parallel across one of the 10 k resistors. The voltage source is 24 V. The total current in the circuit is900 
A
A9 mA
90 mA
800 A
ADiscussion:
23 comments Page 1 of 3.
Ramu said:
1 decade ago
(30+20+10)/0.066 = 900
Nadarajan V said:
1 decade ago
20k ohm + ((20*10)/(20+10)) = 26.67k ohm
V= IR => I= V/R
=> I= 24V/26.67k ohm
=> I= 24V/26670ohm
=> I= 0.0008998875A
=> I= 899.8875 micro Amps
so 900 micro Amps is the correct answer.
V= IR => I= V/R
=> I= 24V/26.67k ohm
=> I= 24V/26670ohm
=> I= 0.0008998875A
=> I= 899.8875 micro Amps
so 900 micro Amps is the correct answer.
Anand said:
1 decade ago
Nice Explanation Nadarajan...
Pradeep said:
1 decade ago
@Nadarajan :Thank you
Uday said:
1 decade ago
[{(20*10)/30}+10+10]=80/3 then
v=24v now
i=v/r=24/(80/3)*1/1000=(72/80)1/*1000=0.9/1000=0.0009=900microA
v=24v now
i=v/r=24/(80/3)*1/1000=(72/80)1/*1000=0.9/1000=0.0009=900microA
Shailaja said:
1 decade ago
10K 10K 10K
------^^^^^-----^^^^-----^^^^------
| | |
| | |
| > |
| >20K OHM 24 V
| > |
| | |
------------------------------------ Is this circuit diagram is correct?
------^^^^^-----^^^^-----^^^^------
| | |
| | |
| > |
| >20K OHM 24 V
| > |
| | |
------------------------------------ Is this circuit diagram is correct?
Pukhraj said:
1 decade ago
Thanks nadarajan.
Arun said:
1 decade ago
R=20+(20*10)/30=26.67.
I=V/R=24/26.67=.899 mA= 900uA.
I=V/R=24/26.67=.899 mA= 900uA.
Trupti said:
1 decade ago
V = IR.
I = V/R.
R1 = R2 = R3 = 10 kohm.
One 20 kohm resistor is parallel with one of the 10 kohm resistor.
So say R4 = 20 kohm parallel with R1.
Total resistance= (R1*R4/R1+R4)+R2+R3 = 26666.66 ohms.
I = 24/26666.66 = 900 uA.
I = V/R.
R1 = R2 = R3 = 10 kohm.
One 20 kohm resistor is parallel with one of the 10 kohm resistor.
So say R4 = 20 kohm parallel with R1.
Total resistance= (R1*R4/R1+R4)+R2+R3 = 26666.66 ohms.
I = 24/26666.66 = 900 uA.
ALI said:
10 years ago
R = R1+R2+R3.
R = 10+10+6.66666 = 26.66666 K ohm.
1/R3 = 1/10+1/20.
R3 = 6.666666.
I =V/R = 24/26666.67 = 90 m A.
R = 10+10+6.66666 = 26.66666 K ohm.
1/R3 = 1/10+1/20.
R3 = 6.666666.
I =V/R = 24/26666.67 = 90 m A.
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