Electrical Engineering - Series-Parallel Circuits - Discussion

Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 19)
19.
A balanced Wheatstone bridge consists of an RV of 3,500 , an R2 of 200 , and an R3 of 680 . The value of RUNK is
680
1,029
200
880
Answer: Option
Explanation:
No answer description is available. Let's discuss.
Discussion:
19 comments Page 1 of 2.

Sid said:   8 years ago
Isn't the formula for Wheatstone bridge is R1/R2 = R3/R4?

Everyone is solving the questions with the formula R1 * R2 = R3 * R4 yet getting the correct answer.

Can anyone please correct my approach?
(1)

Prakash said:   1 decade ago
R1*R2 = R3*R4.

So R4 = (R1*R2)/R3.

R4 = (3500*200)/680 = 1029 Ohm.
(1)

Bharath said:   10 years ago
Guys Rv and Runx are names given to R1 and R4.
(1)

Shital said:   2 years ago
I think it seems wrong.

The Wheatstone bridge formula is R1/R2 = R3/R4.

Gopal said:   1 decade ago
3500*200/680=1029

Harsh said:   8 years ago
Here r2 is Rv and r3 is Runk. Apply the formula r1/r2=r3/r4 you will get the correct answer.

Jay said:   8 years ago
Can anyone explain why the R1*R2 = R3*R4 approach?

SANDEEP K PATIL said:   8 years ago
@All.

R UNK means = unknown resistance.

Jagan said:   9 years ago
When the bridge is balanced the formula will be. Ra/Rx = R1/R2.

Now we can get 1029.

Renu said:   9 years ago
Thank you for the answer and explanation.


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