Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 3)
3.
The output of a certain voltage divider is 12 V with no load. When a load is connected, the output voltage
Discussion:
24 comments Page 1 of 3.
K.Rekha said:
1 decade ago
Why a load is connected, the output voltage decreases ?
Dhanish said:
1 decade ago
Because when we apply load (resistance) then we create hindrance against the flow of electrons and hence voltage decreases like the example of bottle when we make a hole in bottle then level of water decreases gradually.
Ritesh said:
1 decade ago
@Dhanish you are correct.
Ashish said:
1 decade ago
Answer is A.
Because when we connect load than current drawn from grid will be increase. Than transmission losses will increase. So voltage at load side will decrease.
Because when we connect load than current drawn from grid will be increase. Than transmission losses will increase. So voltage at load side will decrease.
Roshan said:
1 decade ago
Answer is A.
In no load case the o/p voltage is 12v but when me connect a load across it takes some power (volt) due to that o/p voltage is decreases.
In no load case the o/p voltage is 12v but when me connect a load across it takes some power (volt) due to that o/p voltage is decreases.
Rohit said:
1 decade ago
When we connect the load some voltage is drop at the load so total o/p volt. is decreases.
Roshan said:
1 decade ago
When there is no load there is no current hence the internal resistance drop is zero...but when we connect a load current starts flowing. Hence some vol drop will appear across internal resistance.
Hence from KVL V-Ir=Vo.
Hence from KVL V-Ir=Vo.
Spurgeon said:
1 decade ago
What is a voltage divider?
Shibam jha said:
1 decade ago
Initially supply voltage = output voltage.
After adding load:
Output voltage = [supply voltage - I*resistance of load] (from KVL).
So the output voltages decreases.
After adding load:
Output voltage = [supply voltage - I*resistance of load] (from KVL).
So the output voltages decreases.
Shibam jha said:
1 decade ago
@Spurgeon: voltage divider is basically a circuit in which output voltage is fraction of the supply voltage. Actually in the secondary side of transformer there is voltage divider. So when decider moves number of turns that is impedance changes and accordingly we get different voltages in the load side. If there will be two impedance in series and we use V.D between the impedance then output voltages is.
V(output) = V(input) *Z2/Z1+Z2.
V(output) = V(input) *Z2/Z1+Z2.
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