Electrical Engineering - Series-Parallel Circuits - Discussion

Assuming that from a voltage divider circuit with two resistors given (R1 and R2), we added a load resistance RL parallel to R2, making it a simple series-parallel circuit.

Note that (R2 parallel to RL) will decrease the total resistance.

1. Decreasing the total resistance will increase the total current drawn from the source: IT = 'VT/RT".
2. If the current drawn from the source increase, the current across R1 will also increase.
3. Consequently, the voltage drop across R1 will also increase, leaving less voltage for the output.
4. Therefore, the readings across Vo will decrease.

Vo = Vs (with no load).

By voltage divider.
Vo = Vs(R/(R+RL)) (with load).

RL = across the load.

So the Voltage OUTPUT WILL DECREASE!

ASSUME A VALUE SO THAT YOU WILL UNDERSTAND!

When there is no load there is no current hence the internal resistance drop is zero. But when we connect a load current starts flowing. Hence some vol drop will appear across the internal resistance.

The output is measured across the load, if we assume ideal condition, the circuit with 0 resistance in wires, the entire voltage drops across the load so output voltage should remain constant.

When you connect the load,it means you have completed the circuit for current flow through it. Now the; Output voltage = Supply EMF (voltage at no load) - voltage drop (across the internal resistance of the source/supply).

That's why the output terminal voltage decrease in the case of a load. Option A.

Can anyone explain with formula?

Think simple as voltage divider applied in series circuit so if we connect more load automatically voltage decreases because voltage is divided.

Let consider in this divider, Rx is the resistance of that resistor. Now we connect some load (its resistance may less or more than Rx) since load and divider resistance is in parallel system resistance will decrease. The current will increase and the voltage drop will in accordance with current. Conclusion voltage will decrease across that Rx.

Hello, everyone, I faced an issue with voltage drop.

I am using 24v supply source and connecting few load in parallel with it but when I am connecting one of their load voltage decreases by 10v at the source side and when I am removing this load from circuit voltage increases to 24v.

Please help me to solve my issue.

It's all about series parallel circuit, generally voltage devices when there is series circuit and in parallel circuit voltage remain same.

So here load is connected it means another series load added means voltage must decrease.