Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 3)
3.
The output of a certain voltage divider is 12 V with no load. When a load is connected, the output voltage
Discussion:
24 comments Page 2 of 3.
Bharath b Kumar said:
9 years ago
Voltage divider rule is applicable to only series connected elements. In parallel circuit even though if you increase load are decrease voltage remains same.
In this ex your connecting the load (nothing but resistance are inductance) definitely there would be drop of voltage across this load elements that's it.
In this ex your connecting the load (nothing but resistance are inductance) definitely there would be drop of voltage across this load elements that's it.
Raji said:
10 years ago
@Shibam Jha.
I have some doubt. Why are you using this formula?
I have some doubt. Why are you using this formula?
Pruthvi said:
10 years ago
The output of certain divider is 12v that means the divider connected in parallel voltage remains same when load was connected it became series with divider hence voltage changes that is it decreases.
Khalique said:
1 decade ago
Voltage divider V(Rx) = Vi*Rx/(Rt). According to me voltage should increase if we are measuring output voltage across the resistor having resistance Rx.
Shibam jha said:
1 decade ago
@Spurgeon: voltage divider is basically a circuit in which output voltage is fraction of the supply voltage. Actually in the secondary side of transformer there is voltage divider. So when decider moves number of turns that is impedance changes and accordingly we get different voltages in the load side. If there will be two impedance in series and we use V.D between the impedance then output voltages is.
V(output) = V(input) *Z2/Z1+Z2.
V(output) = V(input) *Z2/Z1+Z2.
Shibam jha said:
1 decade ago
Initially supply voltage = output voltage.
After adding load:
Output voltage = [supply voltage - I*resistance of load] (from KVL).
So the output voltages decreases.
After adding load:
Output voltage = [supply voltage - I*resistance of load] (from KVL).
So the output voltages decreases.
Spurgeon said:
1 decade ago
What is a voltage divider?
Roshan said:
1 decade ago
When there is no load there is no current hence the internal resistance drop is zero...but when we connect a load current starts flowing. Hence some vol drop will appear across internal resistance.
Hence from KVL V-Ir=Vo.
Hence from KVL V-Ir=Vo.
Rohit said:
1 decade ago
When we connect the load some voltage is drop at the load so total o/p volt. is decreases.
Roshan said:
1 decade ago
Answer is A.
In no load case the o/p voltage is 12v but when me connect a load across it takes some power (volt) due to that o/p voltage is decreases.
In no load case the o/p voltage is 12v but when me connect a load across it takes some power (volt) due to that o/p voltage is decreases.
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