Electrical Engineering - Series-Parallel Circuits - Discussion
Discussion Forum : Series-Parallel Circuits - General Questions (Q.No. 3)
3.
The output of a certain voltage divider is 12 V with no load. When a load is connected, the output voltage
Discussion:
24 comments Page 2 of 3.
Khalique said:
1 decade ago
Voltage divider V(Rx) = Vi*Rx/(Rt). According to me voltage should increase if we are measuring output voltage across the resistor having resistance Rx.
Pruthvi said:
1 decade ago
The output of certain divider is 12v that means the divider connected in parallel voltage remains same when load was connected it became series with divider hence voltage changes that is it decreases.
Raji said:
1 decade ago
@Shibam Jha.
I have some doubt. Why are you using this formula?
I have some doubt. Why are you using this formula?
Bharath b Kumar said:
10 years ago
Voltage divider rule is applicable to only series connected elements. In parallel circuit even though if you increase load are decrease voltage remains same.
In this ex your connecting the load (nothing but resistance are inductance) definitely there would be drop of voltage across this load elements that's it.
In this ex your connecting the load (nothing but resistance are inductance) definitely there would be drop of voltage across this load elements that's it.
Satheesh Gour said:
10 years ago
It's all about series parallel circuit, generally voltage devices when there is series circuit and in parallel circuit voltage remain same.
So here load is connected it means another series load added means voltage must decrease.
So here load is connected it means another series load added means voltage must decrease.
Ajay said:
9 years ago
Hello, everyone, I faced an issue with voltage drop.
I am using 24v supply source and connecting few load in parallel with it but when I am connecting one of their load voltage decreases by 10v at the source side and when I am removing this load from circuit voltage increases to 24v.
Please help me to solve my issue.
I am using 24v supply source and connecting few load in parallel with it but when I am connecting one of their load voltage decreases by 10v at the source side and when I am removing this load from circuit voltage increases to 24v.
Please help me to solve my issue.
Subhash said:
8 years ago
Let consider in this divider, Rx is the resistance of that resistor. Now we connect some load (its resistance may less or more than Rx) since load and divider resistance is in parallel system resistance will decrease. The current will increase and the voltage drop will in accordance with current. Conclusion voltage will decrease across that Rx.
Amresh said:
8 years ago
Think simple as voltage divider applied in series circuit so if we connect more load automatically voltage decreases because voltage is divided.
Rabind shah said:
8 years ago
Can anyone explain with formula?
Sikandar said:
6 years ago
When you connect the load,it means you have completed the circuit for current flow through it. Now the; Output voltage = Supply EMF (voltage at no load) - voltage drop (across the internal resistance of the source/supply).
That's why the output terminal voltage decrease in the case of a load. Option A.
That's why the output terminal voltage decrease in the case of a load. Option A.
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