Electrical Engineering - Series Circuits - Discussion
Discussion Forum : Series Circuits - General Questions (Q.No. 8)
8.
The following resistors (one each) are connected in a series circuit: 470 
, 680 , 1 k, and 1.2 k. The voltage source is 20 V. Current through the 680 resistor is approximately
, 680 , 1 k, and 1.2 k. The voltage source is 20 V. Current through the 680 resistor is approximatelyDiscussion:
23 comments Page 1 of 3.
Amala Joseph J said:
8 years ago
@Ashwini S.
We know that, in a series circuit the current flowing through all resistance are same.
So the current flowing through 680-ohm resistor or 1K-ohm or any other resistor connected in a series circuit will be equal to the total current flowing through the circuit.
Hence. if you want to reduce the amount of current flowing through the circuit, then the resistor should not be connected in series. Instead of that you have to connect it in parallel.
This is electrical basics.
We know that, in a series circuit the current flowing through all resistance are same.
So the current flowing through 680-ohm resistor or 1K-ohm or any other resistor connected in a series circuit will be equal to the total current flowing through the circuit.
Hence. if you want to reduce the amount of current flowing through the circuit, then the resistor should not be connected in series. Instead of that you have to connect it in parallel.
This is electrical basics.
(2)
H C Chalawadi said:
1 decade ago
Here we have four resistors in series so.
470Ohms+680Ohms+1K (1000 Ohms)+1.2K (1200 Ohms) = 3350 ohms.
Connecting these four resisters in series = Connecting only one 3350 ohms resistor,
V = 20 V.
I = ?
R = 3350 ohms.
I = V/R = 20/3350 = 0.005970149 amps.
Multiply with 1000 as we want result in mA.
So 0.005970149*1000 = 5.970149 mA which is almost equal to 6mA. So Answer is 6mA.
470Ohms+680Ohms+1K (1000 Ohms)+1.2K (1200 Ohms) = 3350 ohms.
Connecting these four resisters in series = Connecting only one 3350 ohms resistor,
V = 20 V.
I = ?
R = 3350 ohms.
I = V/R = 20/3350 = 0.005970149 amps.
Multiply with 1000 as we want result in mA.
So 0.005970149*1000 = 5.970149 mA which is almost equal to 6mA. So Answer is 6mA.
(1)
Thirumalesh said:
1 decade ago
Equivalent resistance Req = 470+680+1000+1200 = 3350 ohms
"All are connected in series" and
we know that current (I) is same Series connection.
So I=V/Req = 20/3350
I = 6 mA.
"All are connected in series" and
we know that current (I) is same Series connection.
So I=V/Req = 20/3350
I = 6 mA.
Rojalin bhutia said:
1 decade ago
Series current is same, but voltage drop across all the resistors are different.
Here total voltage 20v.
R=680 ohms, 470, 1200, 1000.
Ohms law V=IR.
I = 20/3.35k.
= 5.97 milli amps.
Here total voltage 20v.
R=680 ohms, 470, 1200, 1000.
Ohms law V=IR.
I = 20/3.35k.
= 5.97 milli amps.
Srinuivas said:
1 decade ago
In series current is same ,but voltage dropacross all the resistors are different
here total voltage 20v
r=680 ohms ,470,1200,1000
ohms law v=ir
i=20/3.35k
=5.97milliamps
here total voltage 20v
r=680 ohms ,470,1200,1000
ohms law v=ir
i=20/3.35k
=5.97milliamps
Nagendra said:
1 decade ago
Current flowing will be same through out the circuit..
So total resistors = 470 + 680 + 1k + 1.2K = 3.35 kohms
i=v/r
20/3.35k
=5.97mA
which is equal to 6mA
So total resistors = 470 + 680 + 1k + 1.2K = 3.35 kohms
i=v/r
20/3.35k
=5.97mA
which is equal to 6mA
ARUN KUMAR M said:
1 decade ago
According to OHMS LAW V = IR.
In a series circuit, current is same, voltage is different.
R = R1+R2+R3+R4 = 3350 V = 20.
I = 20/3350.
I = 5.9 mA.
In a series circuit, current is same, voltage is different.
R = R1+R2+R3+R4 = 3350 V = 20.
I = 20/3350.
I = 5.9 mA.
(5)
Sandeep chandraker said:
1 decade ago
Total resistors = 470 + 680 + 1k + 1.2K = 3.35 kohms
V=20v
V=IR
20=I*3.35
I=20/3.35K
I=5.97mA
which is equal to 6mA
V=20v
V=IR
20=I*3.35
I=20/3.35K
I=5.97mA
which is equal to 6mA
RAJAN202509 said:
1 decade ago
In series connection, the current across all the resister is same. So to get the answer. See above solutions.
Pushpendra singh said:
1 decade ago
Total resistors =470/1000+680/1000+1+1. 2=3. 35 kohms.
Voltage = 20V.
V=IR.
I=V/R.
=20/3. 35k.
I=5. 97mA.
Voltage = 20V.
V=IR.
I=V/R.
=20/3. 35k.
I=5. 97mA.
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